2012-03-10 66 views
2

如何使用log4cpp记录多个字符串?如何一次性用log4cpp记录多个变量?

E.g.如果我想记录所有的argv的主:

#include <iostream> 
#include <log4cpp/Category.hh> 
#include <log4cpp/FileAppender.hh> 
#include <log4cpp/PatternLayout.hh> 

using namespace std; 

int main(int argc, char* argv[]) { 
    log4cpp::Appender *appender = new log4cpp::FileAppender("FileAppender","mylog"); 
    log4cpp::PatternLayout *layout = new log4cpp::PatternLayout(); 
    layout->setConversionPattern("%d: %p - %m %n"); 
    log4cpp::Category& category = log4cpp::Category::getInstance("Category"); 
    appender->setLayout(layout); 
    category.setAppender(appender); 
    category.setPriority(log4cpp::Priority::INFO); 

    category.info("program started"); // this works fine, I see it in the logfile 

    for(int i=0; i<argc; ++i) { 
     // next line does not compile: 
     category.info("argv["<<i<<"] = '"<<argv[i]<<"'"); 
    } 

    return 0; 
} 

category.info("argv["<<i<<"] = '"<<argv[i]<<"'"); 

不能编译。很明显,记录器不能用作ostream。什么是log4cpp方式记录这样的事情,最好立刻?

回答

5

你有两个选择:

  • 使用printf-style formatting

    for (int i = 0; i < argc; ++i) 
    { 
        category.info("argv[%d] = '%s'", i, argv[i]); 
    } 
    
  • 使用infoStream()

    for (int i = 0; i < argc; ++i) 
    { 
        category.infoStream() << "argv[" << i << "] = '" << argv[i] << "'"; 
    } 
    

我会去后者。

+0

即:预格式化一个字符串(使用printf或ostringstream)然后记录该字符串? – 2012-03-10 11:01:44

+0

@JörgBeyer:无需预格式化。请看我更新的答案。 – Johnsyweb 2012-03-10 11:28:28

+1

酷,** category.infoStream()**是我想要的,但没有找到。 – 2012-03-10 11:29:15