我需要将SQL转换为Transbase

Question

我需要将SQL转换为transbase，因为当我在Transbase中使用下面的脚本时，我得到一个相当丑陋的错误。

我的脚本：

SELECT STR_ID, TEX_TEXT AS STR_DES_TEXT, IF(EXISTS(SELECT * FROM tof_SEARCH_TREE AS SEARCH_TREE2 
    WHERE SEARCH_TREE2.STR_ID_PARENT <> tof_SEARCH_TREE.STR_ID 
), 1, 0) AS DESCENDANTS 
    FROM tof_SEARCH_TREE 
    INNER JOIN tof_DESIGNATIONS ON DES_ID = STR_DES_ID 
    INNER JOIN tof_DES_TEXTS ON TEX_ID = DES_TEX_ID 
WHERE STR_ID_PARENT <> NULL AND DES_LNG_ID = 21 AND EXISTS (
SELECT * FROM tof_LINK_GA_STR 
    INNER JOIN tof_LINK_LA_TYP ON LAT_TYP_ID = 3822 AND LAT_GA_ID = LGS_GA_ID 
    INNER JOIN tof_LINK_ART ON LA_ID = LAT_LA_ID 
WHERE LGS_STR_ID = STR_ID 
); 

我的错误是：

compile error: ')' expected: at line >2<: FROM tof_SEARCH_TREE AS SEARCH_TREE2

Answer 1

我没有用过Transbase，但它声称支持ANSI SQL功能。 if()不是ANSI功能，所以你可以尝试：

SELECT STR_ID, TEX_TEXT AS STR_DES_TEXT, 
     (CASE WHEN EXISTS (SELECT 1 
          FROM tof_SEARCH_TREE AS SEARCH_TREE2 
          WHERE SEARCH_TREE2.STR_ID_PARENT <> tofSEARCH_TREE.STR_ID 
         ) 
      THEN 1 ELSE 0 
     END) AS DESCENDANTS 
FROM tof_SEARCH_TREE INNER JOIN 
    tof_DESIGNATIONS 
    ON DES_ID = STR_DES_ID INNER JOIN 
    tof_DES_TEXTS 
    ON TEX_ID = DES_TEX_ID 
WHERE STR_ID_PARENT IS NOT NULL AND 
     DES_LNG_ID = 21 AND 
     EXISTS (SELECT 1 
       FROM tof_LINK_GA_STR INNER JOIN 
        tof_LINK_LA_TYP 
        ON LAT_TYP_ID = 3822 AND LAT_GA_ID = LGS_GA_ID INNER JOIN 
        tof_LINK_ART 
        ON LA_ID = LAT_LA_ID 
       WHERE LGS_STR_ID = STR_ID 
      ); 

我觉得这是符合ANSI标准。而且，它也应该在MySQL中工作。