查询retuerning资源ID＃10

我想显示具有特定列名称的行数。当我执行查询时，没有显示错误，但给出的输出只是资源ID＃10。我是一名在PHP和MySQL领域的初学者。谁能帮我吗？我试着下面的代码给出查询retuerning资源ID＃10

$sql ="SELECT column1,column2 FROM table1 WHERE user_id='name' GROUP BY time_stamp";  
    $result = mysql_query($sql); 
    $count=1; 
    while($row = mysql_fetch_array($result)) { 
     echo "<form action=table2.php method=GET>"; 
     echo"<tr>"; 
     $row_no="SELECT COUNT(time_stamp) FROM table1"; 
     $row_num = mysql_query($row_no); 



     echo "<td>" .$count. "</td>"; 
     echo "<td>" .$row["column1"]. "</td>"; 
     echo "<td>" .$row["column2"]. "</td>"; 
     echo "<td>" .$row_num. "</td>"; 
     echo "<td>" ."<input class=btn type=submit value=Delete". "></td>"; 

     echo"</tr>"; 
     echo "</form>"; 
     $count=$count+1; 
    }

来源

2015-10-05 Akshay

在'while循环中'mysql_query（$ row_no）''后面使用'mysql_fetch_row（）' – Suyog

也查询应该是'SELECT COUNT（time_stamp）'作为count FROM table1' – Suyog

不**使用'mysql_'nothing什么都不做，它是*弃用*功能。您需要将其更改为'mysqli_'函数或更好的'PDO'对象; –

您需要获取第二查询你执行数组，然后使用它的列呼应

$sql ="SELECT column1,column2 FROM table1 WHERE user_id='name' GROUP BY time_stamp";  
$result = mysql_query($sql); 
$count=1; 
while($row = mysql_fetch_array($result)) { 
    echo "<form action=table2.php method=GET>"; 
    echo"<tr>"; 
    $row_no="SELECT COUNT(time_stamp) AS cnt FROM table1"; 
    $row_num = mysql_query($row_no); 
    $row_num_res = mysql_fetch_array($row_num); 

    echo "<td>" .$count. "</td>"; 
    echo "<td>" .$row["column1"]. "</td>"; 
    echo "<td>" .$row["column2"]. "</td>"; 
    echo "<td>" .$row_num_res["cnt"]. "</td>"; 
    echo "<td>" ."<input class=btn type=submit value=Delete". "></td>"; 

    echo"</tr>"; 
    echo "</form>"; 
    $count=$count+1; 
}

来源

2015-10-05 13:03:53 mynawaz

您需要在第二个查询获取计数。您可以使用mysql_fetch_row

$sql ="SELECT column1,column2 FROM table1 WHERE user_id='name' GROUP BY time_stamp";  
    $result = mysql_query($sql); 
    $count=1; 
    while($row = mysql_fetch_array($result)) 
    { 
     echo "<form action=table2.php method=GET>"; 
     echo"<tr>"; 
     $row_no= mysql_query("SELECT COUNT(time_stamp) as count FROM table1"); 
     $row_num = mysql_fetch_row($row_no); 
     echo "<td>" .$row_num[0]. "</td>"; 
     echo "<td>" .$row["column1"]. "</td>"; 
     echo "<td>" .$row["column2"]. "</td>"; 
     echo "<td>" .$row_num. "</td>"; 
     echo "<td>" ."<input class=btn type=submit value=Delete". "></td>"; 
     echo"</tr>"; 
     echo "</form>"; 
     $count=$count+1; 
    }

注意做到这一点：不要使用mysql_*这些功能已被弃用。改为使用mysqli_*或PDO。

来源

2015-10-05 13:04:52 Suyog

查询retuerning资源ID＃10

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