计算两个日期

Question

之间的区别我已经试过这样

<script type="text/javascript"> 
    var date2=02/09/2009; 
    var date1=03/12/2009; 
    var diff = date1.getDate()-date2.getDate(); 
    alert (diff); 

</script> 

，但它不工作，就是这个原因getDate将工作只为Date？

如何找到这两个日期之间的区别？我无法使用此功能，因为我在salesforce CRM apex页面中添加了JavaScript？

编辑1：INFACT这也太不工作

<script type="text/javascript"> 
    var date2= new Date ("02/09/2009"); 
    var date1= new Date ("04/09/2009"); 
    var diff = date1.getDate()-date2.getDate(); 
    alert (diff); 

</script> 

编辑2：它不是工作压力太大...

<script type="text/javascript"> 
    var date2= "02/09/2009"; 
    var date1= "04/09/2009"; 
    var diff2 = new Date(Date.parse("03/12/2009")- 
         Date.parse("02/09/2009")).toLocaleDateString(); 

// VAR NEW_DATE =新的日期（1970年， 01，01）; // var diff3 = diff2.getDate（）; alert（diff2）;

</script> 

Answer 1

<script language="JavaScript"> 
<!-- 
function dstrToUTC(ds) { 
var dsarr = ds.split("/"); 
var mm = parseInt(dsarr[0],10); 
var dd = parseInt(dsarr[1],10); 
var yy = parseInt(dsarr[2],10); 
return Date.UTC(yy,mm-1,dd,0,0,0); 
} 

function datediff(ds1,ds2) { 
var d1 = dstrToUTC(ds1); 
var d2 = dstrToUTC(ds2); 
var oneday = 86400000; 
return (d2-d1)/oneday; 
} 

// test cases are below 

var a; var b; 

a = "01/09/1999"; 
b = "01/10/1999"; 
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>"); 

a = "01/12/1999"; 
b = "01/19/1999"; 
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>"); 

a = "01/19/1999"; 
b = "01/12/1999"; 
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>"); 

a = "01/03/1999"; 
b = "01/13/1999"; 
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>"); 

a = "04/30/1999"; 
b = "05/01/1999"; 
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>"); 

a = "05/30/1999"; 
b = "06/01/1999"; 
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>"); 

a = "02/28/1999"; 
b = "03/01/1999"; 
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>"); 

a = "02/28/2000"; 
b = "03/01/2000"; 
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>"); 

a = "01/01/1999"; 
b = "12/31/1999"; 
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>"); 

a = "01/01/2000"; 
b = "12/31/2000"; 
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>"); 

a = "12/15/1999"; 
b = "01/15/2001"; 
document.write("From "+a+" to "+b+" is "+datediff(a,b)+" day(s)<br>"); 

// --> 
</script> 

Answer 2

Here解释如何找到两个日期在JavaScript

Answer 3

diff.setTime(Math.abs(date1.getTime() - date2.getTime())); 

timediff = diff.getTime(); 

weeks = Math.floor(timediff/(1000 * 60 * 60 * 24 * 7)); 
timediff -= weeks * (1000 * 60 * 60 * 24 * 7); 

days = Math.floor(timediff/(1000 * 60 * 60 * 24)); 
timediff -= days * (1000 * 60 * 60 * 24); 

hours = Math.floor(timediff/(1000 * 60 * 60)); 
timediff -= hours * (1000 * 60 * 60); 

mins = Math.floor(timediff/(1000 * 60)); 
timediff -= mins * (1000 * 60); 

secs = Math.floor(timediff/1000); 
timediff -= secs * 1000; 

alert(weeks + " weeks, " + days + " days, " + hours + " hours, " + mins + " minutes, and " + secs + " seconds"); 

Answer 4

1. GETDATE（）返回 月的某一天，你的情况之间的差异：9和12

2. 您应该通过以下内容明确定义日期对象。月份为0，因此0 = 1月，1 = 2月...

   var date2 = new Date（2009，1，9）;

3. 这些是数字，而不是字符串。当你想使用一个字符串的日期，那么你需要的格式，没有什么是可选的：

   var newDate = new Date（“month day，year hours：minutes：seconds”）; var date2 = new Date（“Feb 9，2009 00:00:00”）;

[编辑] 完整的解决方案，如果日期是在格式mm/dd/yyyy的，和差应在天：

<script type="text/javascript"> 
    function daysFromString(dateString) 
    { 
     // split strings at/and return array 
     var splittedString = dateString.split("/"); 
     // make a new date. Caveat: Months are 0-based in JS 
     var newDate = new Date(parseInt(splittedString[2], 10), parseInt(splittedString[0], 10)-1, parseInt(splittedString[1], 10)); 
     // returns days since jan 1 1970 
     return Math.round(newDate.getTime()/(24*3600*1000)); 
    } 

    var dateString2 = "02/09/2009"; 
    var dateString1= "03/12/2009"; 
    var dateDays1 = daysFromString(dateString1); 
    var dateDays2 = daysFromString(dateString2); 
    var diff = dateDays1 - dateDays2; 
    alert (diff); 
</script> 

Answer 5

getDate是Date对象的方法。因为任何文档都明确声明它返回范围为0到31的月份的日期。如果它不是同一个月，则尝试从另一个中减去另一个是没有意义的。

Answer 6

使用Date.parse（DATE1） - Date.parse（DATE2）

Answer 7

DATE2 = 02/09/2009不被认为是一个日期。它以这种方式工作。首先它分为02/09，它返回0.2222222222222222，其已被2009年除（0.2222222222222222/2009）。最后你得到了一个结果date2 = 0.0001106133510314695。它以相同的方式计算date1的结果。

这不是一个有效的操作。如果你想定义日期。请确保您将数据放在正确的日期格式中。

使用任何新的Date（）或Date.parse（ “02/09/2009”）

编辑：

new Date(Date.parse("03/12/2009")-Date.parse("02/09/2009")).toLocaleDateString() Or 
    new Date(date1- date2).toLocaleDateString() 

心不是这项工作..？

编辑：

可能，这将工作..ü可以试试这个..

Date.parse("03/12/2009")-Date.parse("02/09/2009")/(24*60*60*1000) 

，并返回31天

似乎为我工作..但在我的时区花了03/12/2009作为第3个月第11天和2009年

（24 * 60 * 60 * 1000）=毫秒数nds每天

Answer 8

<script type="text/javascript"> 
function GetD() 
{ 
    var date1 = new Date (2009 , 09 , 02); 
    var date2 = new Date (2009 , 12 , 03);   

    var diff = days_between (date1,date2); 
    alert (diff); 
} 
function days_between(date1, date2) { 

    // The number of milliseconds in one day 
    var ONE_DAY = 1000 * 60 * 60 * 24; 

    // Convert both dates to milliseconds 
    var date1_ms = date1.getTime(); 
    var date2_ms = date2.getTime(); 

    // Calculate the difference in milliseconds 
    var difference_ms = Math.abs(date1_ms - date2_ms); 

    // Convert back to days and return 

    return Math.round(difference_ms/ONE_DAY); 
} 
</script> 

Answer 9

是的。 您必须使用日期对象，这样

var d = new Date(2009,9,19); //19th october, months are 0-based 
var d2 = new Date(2009,10,12); 
var diff = (d2 - d)/60000; //diff in minutes 
alert(diff/24); //difference in hours 

Answer 10

尝试

var diff2 = Date.parse("03/12/2009") - Date.parse("02/09/2009"); 

它会给你以毫秒为单位的日期之间的差值。将此数字除以86,400,000，差额将以天为单位。