Javascript Tablesorter将数字排序为字符串

Question

我使用javascript生成JSON表格并使用函数sorttable（）对表格进行排序。

文本排序工作，但数字排序有问题，分拣机认为数字是字符串。

我该如何解决它的分拣机适用于数字？

$(document).ready(function() { 
 
     var hotspots = "[{\"path\": \"src/main/java/tools/generator/data/RecordPart.java\",\"revisions\": 25,\"codeLines\": 18},{\"path\": \"src/main/java/tools/generator/data/RecordTotal.java\", \"revisions\": 55,\"codeLines\": 23},{\"path\": \"src/main/resources/test.xml\",\"revisions\": 102,\"codeLines\": 44},{\"path\": \"src/main/java/tools/generator/helper/MenuHelper.java\",\"revisions\": 4,\"codeLines\": 115}]"; 
 
     
 
     var jsonHotspots = JSON.parse(hotspots); 
 

 
     constructTable(jsonHotspots); 
 
    }); 
 

 
//Construct Table 
 

 
function constructTable(json) { 
 
     console.debug("Table : " + json); // this will show the info it in firebug console 
 

 
     var tbl=$("<table/>").attr("id","mytable"); 
 
     $("#div1").append(tbl); 
 

 
     var tr="<tr>"; 
 
     var td1='<td onclick="sortTable(0)" >Path</td>'; 
 
     var td2='<td onclick="sortTable(1)" >Revision</td>'; 
 
     var td3='<td onclick="sortTable(2)" >CodeLines</td></tr>'; 
 
     $("#mytable").append(tr+td1+td2+td3); 
 

 
     for(var i=0;i < json.length ; i++) 
 
     { 
 
      var tr="<tr>"; 
 
      var td1="<td>"+json[i]["path"]+"</td>"; 
 
      var td2="<td>"+json[i]["revisions"]+"</td>"; 
 
      var td3="<td>"+json[i]["codeLines"]+"</td></tr>"; 
 

 
      $("#mytable").append(tr+td1+td2+td3); 
 
     } 
 
} 
 

 

 

 
//TableSorter 
 

 
function sortTable(n) { 
 
     var table, rows, switching, i, x, y, shouldSwitch, dir, switchcount = 0; 
 
     table = document.getElementById("mytable"); 
 
     switching = true; 
 
     dir = "asc"; 
 
     while (switching) { 
 
     switching = false; 
 
     rows = table.getElementsByTagName("TR"); 
 
     for (i = 1; i < (rows.length - 1); i++) { 
 
      shouldSwitch = false; 
 
      x = rows[i].getElementsByTagName("TD")[n]; 
 
      y = rows[i + 1].getElementsByTagName("TD")[n]; 
 
      if (dir == "asc") { 
 
      if (x.innerHTML.toLowerCase() > y.innerHTML.toLowerCase()) { 
 
       shouldSwitch= true; 
 
       break; 
 
      } 
 
      } else if (dir == "desc") { 
 
      if (x.innerHTML.toLowerCase() < y.innerHTML.toLowerCase()) { 
 
       shouldSwitch= true; 
 
       break; 
 
      } 
 
      } 
 
     } 
 
     if (shouldSwitch) { 
 
      rows[i].parentNode.insertBefore(rows[i + 1], rows[i]); 
 
      switching = true; 
 
      switchcount ++; 
 
     } else { 
 
      if (switchcount == 0 && dir == "asc") { 
 
      dir = "desc"; 
 
      switching = true; 
 
      } 
 
     } 
 
     } 
 
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> 
 

 
<div> 
 
    <pre id=mytable></pre> 
 
</div>

Answer 1

解决方案

行简单if看，如果是行0或1 & 2，如果是1或2我的字符串转换为int这作品。

function sortTable(n) { 
      var table, rows, switching, i, x, y,x1,y1, shouldSwitch, dir, switchcount = 0; 
      table = document.getElementById("mytable"); 
      switching = true; 
      dir = "asc"; 
      while (switching) { 
      switching = false; 
      rows = table.getElementsByTagName("TR"); 
      for (i = 1; i < (rows.length - 1); i++) { 
       shouldSwitch = false; 
        if(n == 0) { 
         x = rows[i].getElementsByTagName("TD")[n]; 
         y = rows[i + 1].getElementsByTagName("TD")[n]; 
         if (dir == "asc") { 
          if (x.innerHTML.toLowerCase() > y.innerHTML.toLowerCase()) { 
           shouldSwitch= true; 
           break; 
          } 
         } else if (dir == "desc") { 
          if (x.innerHTML.toLowerCase() < y.innerHTML.toLowerCase()) { 
           shouldSwitch= true; 
           break; 
          } 
         } 
        }else{ 
         x = rows[i].getElementsByTagName("TD")[n].innerHTML; 
         y = rows[i + 1].getElementsByTagName("TD")[n].innerHTML; 
         x1 = Number(x) 
         y1 = Number(y) 
         if (dir == "asc") { 
          if (x1 > y1) { 
           shouldSwitch= true; 
           break; 
          } 
         } else if (dir == "desc") { 
          if (x1 < y1) { 
           shouldSwitch= true; 
           break; 
          } 
         } 
        } 
      } 
      if (shouldSwitch) { 
       rows[i].parentNode.insertBefore(rows[i + 1], rows[i]); 
       switching = true; 
       switchcount ++; 
      } else { 
       if (switchcount == 0 && dir == "asc") { 
       dir = "desc"; 
       switching = true; 
       } 
      } 
      } 
     }