为什么我不能在B类初始化列表中访问基类A的成员?从C++中导出问题
class A
{
public:
explicit A(int a1):a(a1)
{
}
explicit A()
{
}
public:
int a;
public:
virtual int GetA()
{
return a;
}
};
class B : public A
{
public:
explicit B(int a1):a(a1) // wrong!, I have to write a = a1 in {}. or use A(a1)
{
}
int GetA()
{
return a+1;
}
};
class C : public A
{
public:
explicit C(int a1):a(a1)
{
}
int GetA()
{
return a-1;
}
};
我已经改变了措辞,使问题更加具体:您不能从初始化列表中访问字段,而您确实可以从构造函数体中访问它。 – 2009-08-21 06:40:16