PHP得到大部分重复阵列

Question

值我有一个这样的数组中的数组：

Array 
(
    [0] => Array 
     (
      [name] => B 
      [id] => 924572 
     ) 

    [1] => Array 
     (
      [name] => A 
      [id] => 120689 
     ) 

    [2] => Array 
     (
      [name] => A 
      [id] => 120689 
     ) 

    [3] => Array 
     (
      [name] => C 
      [id] => 919644 
     ) 

    [4] => Array 
     (
      [name] => A 
      [id] => 120689 
     ) 

    [5] => Array 
     (
      [name] => B 
      [id] => 924572 
     ) 
) 

我怎样才能从对象中重复最多的值命名为name和id？

我已经尝试下面的代码，但我得到了一个错误：Warning: array_count_values(): Can only count STRING and INTEGER values!

$count = array_count_values($info); 
arsort($count); 
$popular = array_keys($count); 
echo $popular[0]; 

任何关于修复这个问题？

Answer 1

“序列化方式” 的出现，从而搜索最多次的夫妇（name，id）：

$out = array(); 
foreach($arr as $el){ 
    $key = serialize($el); 
    if (!isset($out[$key])) 
     $out[$key]=1; 
    else 
     $out[$key]++; 
} 

arsort($out); 

foreach($out as $el=>$count){ 
    $item = unserialize($el); 
    echo "Name = ".$item['name'].' ID = '.$item['id'].' Count = '.$count.'<br/>'; 
} 

输出：

Name = A ID = 120689 Count = 3 
Name = B ID = 924572 Count = 2 
Name = C ID = 919644 Count = 1 

更新 Without loop

..... 
arsort($out); 

$most = unserialize(key($out)); 
$most_count = array_shift($out); 

echo $most['name']; 
echo $most['id']; 
echo $most_count; 

输出：

A 
120689 
3 

Answer 2

基于PHP中的finding the mode和mapping。这会工作吗？

$name_array = array_map(function($x) {return $x["name"];}, $info); 
$count = array_count_values($name_array); 
$mode = array_keys($count, max($count)); 

要返回的"name"数组，"id"双使用：

$return_value = array_filter($info, function($x) use ($mode) { return (in_array($x["name"], $mode));}); 

Answer 3

也许你可以使用此解决方案的工作：

<?php 
$info = array(
    array(
     "name" => "B", 
     "id" => 924572 
    ), 
    array(
     "name" => "A", 
     "id" => 120689 
    ), 
    array(
     "name" => "A", 
     "id" => 120689 
    ), 
    array(
     "name" => "C", 
     "id" => 919644 
    ), 
    array(
     "name" => "A", 
     "id" => 120689 
    ), 
    array(
     "name" => "B", 
     "id" => 924572 
    ), 
); 

$result = array(); 
foreach ($info as $infoKey => $infoValue) { 
    foreach ($infoValue as $itemKey => $itemValue) { 
     if ($itemKey != "name") { 
      continue; 
     } 
     if (array_key_exists($itemValue, $result)){ 
      $result[$itemValue]++; 
      continue; 
     } 
     $result[$itemValue] = 1; 
    } 
} 
arsort($result); 
var_dump($result); 

会导致：

array (size=3) 
    'A' => int 3 
    'B' => int 2 
    'C' => int 1 

Answer 4

更线性的解决方案。

$arr = Array 
(
    Array 
     (
      "name" => "B", 
      "id" => 924572 
     ), 

    Array 
     (
      "name" => "A", 
      "id" => 120689 
     ), 

    Array 
     (
      "name" => "A" , 
      "id" => 120689 
     ), 

    Array 
     (
      "name" => "C", 
      "id" => 919644 
     ), 

    Array 
     (
      "name" => "A", 
      "id" => 120689 
     ), 

    Array 
     (
      "name" => "B", 
      "id" => 924572 
     )); 

$countArr = Array(); 

for($i = 0; $i < count($arr); $i++) 
{ 
    $tmpArr = $arr[$i]; 

    if(array_key_exists($tmpArr["name"],$countArr)) 
     $countArr[$tmpArr["name"]]++; 
    else 
     $countArr[$tmpArr["name"]] = 0; 
} 

arsort($countArr); 
var_dump($countArr); 

Answer 5

利用了array_column（需要PHP 5.5或shim）。

$count_values = array_count_values(array_column($array, 'name')); 

$most_frequent_name = array_search(max($count_values), $count_values); 

然后如果你想用这个名字的所有阵列：

$items = array_filter($array, function ($v) use ($most_frequent_name) { 
    return $v['name'] == $most_frequent_name; 
}); 

如果几个名字可能具有相同的最高频率：

$count_values = array_count_values(array_column($array, 'name')); 

$most_frequent_names = array_keys($count_values, max($count_values)); 

$items = array_filter($array, function ($v) use ($most_frequent_names) { 
    return in_array($v['name'], $most_frequent_names); 
}); 

Answer 6

试试下面的代码。它会给你算的所有元素

function array_icount_values($arr,$lower=true) { 
    $arr2=array(); 
    if(!is_array($arr['0'])){$arr=array($arr);} 
    foreach($arr as $k=> $v){ 
     foreach($v as $v2){ 
     if($lower==true) {$v2=strtolower($v2);} 
     if(!isset($arr2[$v2])){ 
      $arr2[$v2]=1; 
     }else{ 
      $arr2[$v2]++; 
      } 
    } 
    } 
    return $arr2; 
} 

$arr = array_icount_values($array); 
echo "<pre>"; 
print_r($arr);