-1
我有以下查询如何存储itertools查询的输出
for key, group in itertools.groupby(r, lambda item: item['b_id']):
print {key: [x['a_id'] for x in group]}
,让输出
{'0d687c94c5f4': ['12345', '67890']}
{'9ec34be3d535': ['23857', '84596']}
{None: ['d82ebe9815cc']}
如何这个存储到一个变量来访问其内容
试图数据= {key:[x ['a_id'] for x in group]}但是只给出了来自循环的最后一个值{None:['d82ebe9815cc']}
>>data
>>{None: ['d82ebe9815cc']}
你可以这样做:'数据= [KP :[el ['a_id'] for el in g] for k,g in itertools.groupby(...)}'。但相当肯定有一个相当不错的帖子存储groupby的输出我现在找不到:) –