LINQ XML获取父节点的子节点

Question

请在下面找到xml数据。考虑到我知道父节点具有url =“＃”，title =“item 1”和key =“Item1”，我希望使用LINQ查询获得具有键“Sub1”和“Sub2”的节点。

<root> 
<node title="Partner" url="" description="99" roles="GuidIdHere"></node> 
<node title="Test" url="" description="51" roles="8b0c0c4f" key="sample"> 
    <node url="#" title="item 1" description="" key="Item1"> 
     <node url="#" title="Sub 1" description="" key="Sub1" /> 
     <node url="#" title="Sub 2" description="" key="Sub2" /> 
    </node> 
    <node url="#" title="item 2" description="" key="Item2" /> 
    <node url="#" title="item 3" description="" key="Item3" /> 
</node> 
</root> 

谢谢！

Answer 1

var result = from x in doc.Root.Descendents("node") 
      where (string)x.Attribute("url") == "#" 
       && (string)x.Attribute("title") == "item 1" 
       && (string)x.Attribute("key") == "Item1" 
      from y in x.Elements("node") 
      where (string)x.Attribute("key") == "Sub1" 
       || (string)x.Attribute("key") == "Sub2" 
      select y;