我一直在环顾四周的论坛,并尝试了一切,但我不能让我的按钮禁用后点击它,我刚开始使用PHP,这是我的第一个项目之一。它是一个喜欢和不喜欢的系统。有人知道这个游戏机吗? 当您按下类似按钮或不喜欢按钮时,我希望禁用这两个按钮。1单击然后禁用 - PHP
<!--Like System-->
<center>
<?php
$sql = "SELECT * FROM likes";
$result = mysqli_query($con, $sql);
if (mysqli_num_rows($result) > 0) {
// output data of each row
while($row = mysqli_fetch_assoc($result)) {
?> <h1 class="lcount"><?php echo $row["average"];?> <span class="glyphicon glyphicon-signal"></span></h1></br><?php
}
} else {
echo "0 results";
}
?>
<?php
$sql = "SELECT * FROM likes";
$result = mysqli_query($con, $sql);
if (mysqli_num_rows($result) > 0) {
// output data of each row
while($row = mysqli_fetch_assoc($result)) {
?> <h1 class="lcount"><?php echo $row["like"];?>
<span style="color: green;"class="glyphicon glyphicon-thumbs-up"></span></h1></br>
<?php
}
} else {
echo "0 results";
}
?>
<?php
$sql = "SELECT * FROM likes";
$result = mysqli_query($con, $sql);
if (mysqli_num_rows($result) > 0) {
// output data of each row
while($row = mysqli_fetch_assoc($result)) {
?> <h1 class="lcount"><?php echo $row["dislike"];?>
<span style="color: red;" class="glyphicon glyphicon-thumbs-down"></span></h1>
<?php
}
} else {
echo "0 results";
}
?>
<?php
if(isset($_POST['like'])){
$sql = "UPDATE `likes` SET `like` = `like` + 1 , `average` = `average` + 1";
if (mysqli_query($con, $sql)) {
} else {
echo "Error updating record: " . mysqli_error($con);
}
}
?>
<?php
if(isset($_POST['dislike'])){
$sql = "UPDATE `likes` SET `dislike` = `dislike` + 1 , `average` = `average` - 1";
if (mysqli_query($con, $sql)) {
} else {
echo "Error updating record: " . mysqli_error($con);
}
}
?>
<form type="#" method="post">
<button name="like" type="submit" class="btn btn-success">
<span class="glyphicon glyphicon-thumbs-up"></span></button>
<button name="dislike" type="submit" class="btn btn-danger">
<span class="glyphicon glyphicon-thumbs-down"></span></button>
</form>
</center>
<!--Like System END-->
我觉得像JavaScript将这个 – Maciej
着它只有PHP的工作更适合? – FluffyMe
PHP需要您重新加载页面,因为代码在服务器上执行。 Javascript在浏览器中执行,因此它更适合操作UI,例如禁用按钮。理论上,你可以在PHP中做到这一点,但它可能会非常混乱,总体上不值得。 – Maciej