“数据类型不匹配”中的sqlite3

Question

执行INSERT CASE时，我有两个表，一个是用数据填充

CREATE TABLE `tableX` (`column1` REAL); 

INSERT INTO tableX VALUES (5); 
INSERT INTO tableX VALUES (-3); 

CREATE TABLE `tableY` 
(`rowid` INTEGER PRIMARY KEY, `column2` REAL); 

的INSERT CASE语句是

INSERT INTO tableY SELECT column1, 
CASE WHEN column1 >=0 THEN 1 ELSE 2 END as column2 FROM tableX; 

错误是“数据类型不匹配”中我的数据库浏览器，但它似乎在sqlfiddle工作...没有错误至少

任何帮助，非常感谢！感谢：D！

Answer 1

不是最优雅的解决方案，但它是一个工作。

CREATE TABLE `tableX` (`column1` REAL); 
INSERT INTO tableX VALUES (5); 
INSERT INTO tableX VALUES (-3); 

CREATE TABLE `tableZ` (`column1` REAL, `column3` REAL); 
INSERT INTO tableZ SELECT column1, 
CASE WHEN column1 >=0 THEN 1 ELSE 2 END as column3 FROM tableX; 

CREATE TABLE 'tableY' (`rowid` INTEGER PRIMARY KEY, `column2` REAL) 
INSERT INTO tableY (column2) SELECT column3 FROM tableZ; 

DROP TABLE tableZ;