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我写的辅助服务,以避免USSD请求过程中AlertWindow开幕:Xamarin.Android:如何开启无障碍服务永久
[Service(Label = "BalanceAccessibilityService", Permission = "android.permission.BIND_ACCESSIBILITY_SERVICE")]
[IntentFilter(new string[] { "android.accessibilityservice.AccessibilityService" })]
public class BalanceAccessibilityService : AccessibilityService
{
static readonly string Tag = "SmsService:" + typeof(BalanceAccessibilityService).Name;
protected override void OnServiceConnected()
{
base.OnServiceConnected();
AccessibilityServiceInfo info = new AccessibilityServiceInfo();
info.Flags = AccessibilityServiceFlags.Default;
info.PackageNames = new string[] { "com.android.phone" };
info.EventTypes = EventTypes.WindowStateChanged;
info.FeedbackType = FeedbackFlags.Generic;
SetServiceInfo(info);
}
public override void OnAccessibilityEvent(AccessibilityEvent e)
{
Log.Info(Tag, $"onAccessibilityEvent: type = {e.EventType.ToString()} package = {e.PackageName}");
AccessibilityNodeInfo info = e.Source;
if (e.EventType == EventTypes.WindowStateChanged && !e.PackageName.Equals("com.android.phone"))
return;
if (e.EventType == EventTypes.WindowContentChanged && (info == null || !info.ClassName.Equals("android.widget.TextView")))
return;
if (e.EventType == EventTypes.WindowContentChanged && TextUtils.IsEmpty(info.Text))
return;
if (Build.VERSION.SdkInt >= BuildVersionCodes.M)
PerformGlobalAction(GlobalAction.Back);
else
{
Intent intent = new Intent(Intent.ActionCloseSystemDialogs);
SendBroadcast(intent);
}
}
public override void OnInterrupt()
{
Log.Info(Tag, "OnInterrupt");
}
}
所有的工作,但问题是,当我的应用程序停止设置开关 - >辅助功能 - >服务 - > BalanceAccessibilityService关闭。因此,如果我再次启动我的应用程序而无需再次用手切换此切换器,则我的服务无法启动。现在,我用这样的代码,开关等它在MainActivity的onCreate方法:
Intent intent = new Intent(Settings.ActionAccessibilitySettings);
StartActivityForResult(intent, 0);
,但我认为这是不正常的,因为其他服务,如电网无污染或Android援助是足够多的将其切换一次,他们永远不会自行关闭。 有人可以告诉我我犯了什么错误吗?
您是否每次都使用VS启动您的应用程序? –
@ ElvisXia-MSFT,我不确定我是否试图用手启动它...我现在尝试 – Hermann
@ ElvisXia-MSFT,是的,非常感谢!问题是我使用Xamarin Studio启动我的应用程序。 – Hermann