2016-11-11 77 views
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我想生成行列列总数的交叉表。我试图用gmodels包生成交叉表。输出的外观比普通表格功能要好。桌子的外观很重要,因为最后必须使用Shiny来显示。但问题是我在行和列的末尾获得了列总数和行总数。我怎样才能得到总列作为表中的第一列和第一列。闪亮 - 以第一行/列生成列总数和行总数的交叉表

以下是我的数据示例。

Location <- sample(c("location A","location B","location C","location D","location E"),20,replace = T) 
Brand <- sample(c("Brand A","Brand B","Brand C"),20,replace = T) 
Year <- rep(c("Year 2014","Year 2015"),10) 
Q1 <- sample(1:5,20,replace = T) 
Q2 <- sample(1:5,20,replace = T) 

mydata <- as.data.table(cbind(Location,Brand,Year,Q1,Q2)) 

数据很庞大,因此它是data.table。我使用用于产生交叉表

代码为 -

library("gmodels") 

mydata[,CrossTable(Location,Brand,prop.c = T,prop.r = F,prop.t = F,prop.chisq = F,chisq = F,format = "SPSS")] 

这给出了输出,但总的列是列中的行和结束的结束。列的总数也缺少列%。我如何将总列作为第一行和第一列,并且还有%?

建议出路。

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你可能不想'cbind'在这里。看看'str(mydata)'并注意到所有的cols都被强制为字符串/字符类型。也许你想'reshape2 :: dcast(mydata,Location〜Brand,margin = TRUE)'在这里? – Frank

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既然'CrossTable'返回null,那么你唯一的选择就是根据你的需要修改它的源代码。 –

回答

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你有没有尝试使用sjPlot包....它有一个非常好的功能,sjt.xtab产生交叉表(列联表),类似于你在找什么。它有很多选项可供探索。我在下面使用了其中的几个。您可以查看?sjt.xtab并查看其他可用选项。下面的代码生成具有列百分比的表输出并且具有总列和行。

sjt.xtab(mydata$Location, mydata$Brand, 
     show.col.prc = T, 
     show.summary = F, 
     show.na = F, 
     wrap.labels = 50, 
     tdcol.col = "#f90470", 
     emph.total = T, 
     emph.color = "#3aaee5", 
     use.viewer = T, 
     CSS = list(css.table = "border: 1px solid;", 
        css.tdata = "border: 1px solid;")) 
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我已经找到关于sjPlot包并在这种情况下使用它。是的,这是相当有用的,并符合要求只有东西不给总第1行和第1列。但仍然比其他表格输出更好。我错过了发布答案,并感谢您发布它。 – user1412

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也许这样的事情可能会做?

myCT <- function(mydata) { 
    mydata_ct_n <- dcast.data.table(mydata, Location ~ Brand, margins = T) 
    mydata_ct_n[, all := rowSums(.SD), by = Location] 
    mydata_ct_n <- rbind(mydata_ct_n[, lapply(.SD, sum), .SDcols = 2:ncol(mydata_ct_n)], mydata_ct_n, fill = T) 
    mydata_ct_n$Location[1] <- "all" 
    foocols <- c("all", "Location") 
    setcolorder(mydata_ct_n, c(foocols, setdiff(colnames(mydata_ct_n), foocols))) 

    mydata_ct_p <- copy(mydata_ct_n) 
    for (j in 3:ncol(mydata_ct_p)) { 
    set(mydata_ct_p, j = j, value = as.numeric(mydata_ct_p[[j]])) 
    set(mydata_ct_p, i = 2:nrow(mydata_ct_p), j = j, value = round(100 * mydata_ct_p[2:nrow(mydata_ct_p), j, with = F]/mydata_ct_p[[j]][1], 0)) 
    } 
    set(mydata_ct_p, 1L, 3L:ncol(mydata_ct_p), round(100 * mydata_ct_p[1L, 3L:ncol(mydata_ct_p), with = F]/mydata_ct_p[["all"]][1], 0)) 

    for (j in 3:ncol(mydata_ct_p)) { 
    set(mydata_ct_p, j = j, value = as.character(mydata_ct_p[[j]])) 
    set(mydata_ct_n, j = j, value = as.character(mydata_ct_n[[j]])) 
    set(mydata_ct_p, j = j, 
     value = paste0(mydata_ct_p[[j]], "% (", mydata_ct_n[[j]], ")")) 
    } 
    return(mydata_ct_p) 
} 

Location <- sample(c("location A","location B","location C","location D","location E"),20,replace = T) 
Brand <- sample(c("Brand A","Brand B","Brand C"),20,replace = T) 
Year <- rep(c("Year 2014","Year 2015"),10) 
Q1 <- sample(1:5,20,replace = T) 
Q2 <- sample(1:5,20,replace = T) 
mydata <- as.data.table(cbind(Location,Brand,Year,Q1,Q2)) 

out <- myCT(mydata) 
print(out) 
# all Location Brand A Brand B Brand C 
# 1: 20  all 30% (6) 35% (7) 35% (7) 
# 2: 3 location A 0% (0) 43% (3) 0% (0) 
# 3: 5 location B 33% (2) 14% (1) 29% (2) 
# 4: 5 location C 50% (3) 0% (0) 29% (2) 
# 5: 4 location D 17% (1) 29% (2) 14% (1) 
# 6: 3 location E 0% (0) 14% (1) 29% (2) 
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这很有趣。不过,我需要为相当多的变量生成这样的交叉表输出,并且这将是大约40-50个这样的输出。这将是一个复制的长代码,因此正在gmodels包中寻找一些包OR解决方案。 – user1412

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如果你使它成为一个函数;),让我编辑:) –

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正如提到想在Shiny中生成这个。该代码不会在Shiny中生成所需的输出 – user1412