递增和重复数在Java脚本一个增量循环3次

Question

所以我们的目标是要具备以下条件：

k_1_1 
k_1_2 
k_1_3 

k_2_4 
k_2_5 
k_2_6 

k_3_7 
and so on 

我至今是：

但我认为我的方式关....

while (var qi = 0; qi <= 9; qi++) { 
    for(var ai = 0; ai <= 3; ai++) { 
    var thisName = "k_" + ai + "_" + qi; 
    var thisValue = ""; 
    localStorage.setItem(thisName, thisValue); 
    } 
} 

任何帮助将被apreciated。

谢谢

Answer 1

无需两个回路，如果你用一点点巧思：

for (var i = 0; i <= 9; i++) { 

    var thisName = "k_" + (Math.floor(i/3)+1) + "_" + (i+1); 

    var thisValue = ""; 
    localStorage.setItem(thisName, thisValue); 
} 

Answer 2

您正在使用While循环与For循环参数。 while循环保持循环而条件为TRUE。为什么不切换到For循环像这样（另外，你的气血和AI切换）：

for(var qi = 1; qi <= 9; qi++) { 
for(var ai = 1; ai <= 3; ai++) { 
    var thisName = "k_" + qi + "_" + ai; 
    var thisValue = ""; 
    localStorage.setItem(thisName, thisValue); 
} 
} 

Answer 3

另一种解决方案：

for (var ai = 1; ai <= (27) ; ai++) { // 27 was picked arbitrarily (3 * 9) 
             // set to what ever upper limit you need 

    // the ceiling of the current ai number divided by 3 will give you your qi 
    var qi = Math.ceil((ai/3)); 

    //setting your values 
    var thisName = "k_" + qi + "_" + ai; 
    var thisValue = ""; 

    //reporting 
    console.log(thisName, thisValue); 
}