我使用这行代码作为打印Linux上接口的IP地址的代码段的最后一部分。检查它是否为空
printf ("%s\n", inet_ntoa (((struct sockaddr_in *) &ifr.ifr_addr)->sin_addr));
这很好,但如果我不输入接口名称作为参数,我会得到分段错误。
有没有一种方法来检查,如果这个代码:
inet_ntoa (((struct sockaddr_in *) &ifr.ifr_addr)->sin_addr)
已与参数提供或不?谢谢。
以下是上下文的完整源代码。
/*
* This program is free software: you can redistribute it and/or modify
* it under the terms of the GNU General Public License as published by
* the Free Software Foundation, either version 3 of the License, or
* (at your option) any later version.
*
* This program is distributed in the hope that it will be useful,
* but WITHOUT ANY WARRANTY; without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
* GNU General Public License for more details.
*
* You should have received a copy of the GNU General Public License
* along with this program. If not, see <http://www.gnu.org/licenses/>.
*/
/********************************************************************
* Description:
* Author: John Cartwright <>
* Created at: Wed Jan 13 11:44:29 AEDT 2016
* Computer: ubuntu
* System: Linux 4.3.0-5-generic on x86_64
*
* Copyright (c) 2016 John Cartwright,,, All rights reserved.
*
********************************************************************/
#include <linux/kernel.h> /* for struct sysinfo */
#include <sys/sysinfo.h> /* For the sysinfo struct. */
#include <stdio.h>
#include <string.h> /* for strncpy */
#include <unistd.h> /* for close */
#include <sys/types.h>
#include <sys/socket.h>
#include <sys/ioctl.h>
#include <netinet/in.h>
#include <net/if.h>
#include <stdlib.h> /* For the system() function. */
#include <arpa/inet.h>
#include "info.h"
#define BUF 0x05
int main (int argc, char **argv)
{
int fd;
struct ifreq ifr;
char *myarg1 = argv[2];
char hostname[128];
char *iface = myarg1;
unsigned char *mac;
char command[50];
if (argv[1] == NULL)
{
printf ("********************************************\n");
printf ("* Simple system information. *\n");
printf ("* *\n");
printf ("* IP info: --ip <IFACE> *\n");
printf ("* Print ARP table: --arp *\n");
printf ("* Print sys info: --system *\n");
printf ("********************************************\n");
printf ("\nThe PID of this program was: %i\n", getpid());
}
/* Getting information about the routing table. */
if (argc > 1 && strncmp (argv[1], "--arp", BUF) == 0)
{
printf ("This is the routing table.\n");
char *arg[] = { "cat", "/proc/net/arp", NULL };
execvp (arg[0], arg);
}
if (argc > 1 && strncmp (argv[1], "--system", BUF) == 0)
{
information();
}
if (argc > 1 && strncmp (argv[1], "--hostname", BUF) == 0)
{
gethostname(hostname, sizeof hostname);
printf("Hostname: %s\n", hostname);
}
if (argc > 1 && strncmp (argv[1], "--ip", BUF) == 0)
{
// This code from: http://www.binarytides.com/c-program-to-get-mac-address-from-interface-name-on-linux/
FILE *f;
char line[100] , *p , *c;
char myip;
f = fopen("/proc/net/route" , "r");
while(fgets(line , 100 , f))
{
p = strtok(line , " \t");
c = strtok(NULL , " \t");
if(p!=NULL && c!=NULL)
{
if(strcmp(c , "00000000") == 0)
{
printf("Default interface is : %s \n" , p);
break;
}
}
}
fd = socket(AF_INET, SOCK_DGRAM, 0);
ifr.ifr_addr.sa_family = AF_INET;
strncpy(ifr.ifr_name , iface , IFNAMSIZ-1);
ioctl(fd, SIOCGIFHWADDR, &ifr);
close(fd);
mac = (unsigned char *)ifr.ifr_hwaddr.sa_data;
//display mac address
printf("Mac : %.2x:%.2x:%.2x:%.2x:%.2x:%.2x\n" , mac[0], mac[1], mac[2], \
mac[3], mac[4], mac[5]);
fd = socket (AF_INET, SOCK_DGRAM, 0);
/* I want to get an IPv4 IP address */
ifr.ifr_addr.sa_family = AF_INET;
/* I want IP address attached to the specified interface. */
strncpy (ifr.ifr_name, myarg1, IFNAMSIZ - 1);
ioctl (fd, SIOCGIFADDR, &ifr);
close (fd);
// End binarytides code.
/* display result */
printf ("IP information.\n");
printf("Gateway IP:\n");
strcpy(command, "/sbin/ip route | awk '/default/ { print $3 }'");
system(command);
printf("IP address:\n");
printf ("%s\n", inet_ntoa (((struct sockaddr_in *) &ifr.ifr_addr)->sin_addr));
}
return 0;
}
你真正的问题是“我怎么知道,如果'的ioctl(FD,SIOCGIFADDR,&ifr);'成功了吗?”要回答这个问题,阅读文档'ioctl'。 –
另外你使用'strncpy'不正确,必须空值终止缓冲区 –
一般而言,如代码中的许可条款在堆栈溢出时并不适用 –