-1
所以我有一个变量,需要显示为一天的时间,即3:02,然后使计算关闭该变量,即将7添加到第一个变量,惠灵顿,并显示为3:09。 这是一个简单的问题,它不需要进入日期时间 有没有一种方法可以做到这一点,没有日期?试图显示一个变量作为打印时间
def traintimes():
crofton = wellington + 7
ngaio = crofton + 2
awarua = ngaio + 2
simla = awarua + 2
boxhill = simla + 1
kandallah = boxhill + 2
raroa = kandallah + 2
johnsonville = raroa + 2
print ("Wellington:",wellington,"Crofton Downs:",crofton,"Ngaio:",ngaio,"Awarua Street:",awarua,"Simla Crescent:",simla,"Box Hill:",boxhill,"Kandallah:",kandallah,"Raroa:",raroa,"Johnsonville:",johnsonville)
wellington = int("3:02")
traintimes()
wellington = int("3:28")
traintimes()
wellington = int("3:40")
traintimes()
可能重复[在Python中为datetime.time添加N秒的标准方式是什么?](http://stackoverflow.com/questions/100210/what-is-the-standard-way-to-add -n-seconds-to-datetime-time-in-python) –