随机密码的代码

Question

该代码允许我输入六次以上，也没有打印else声明。我的代码是：

import random 
secret = random.randint(1, 99) 
guess = 0 
tries = 0 
print ('AHOY! I am the Dread Prites Roberts , and i have a secret!') 
print ('It is a number from 1 to 99. I\'ll give you 6 tries ') 

while guess != secret and tries < 6: 
guess = int(input('What is your guess? ')) 
if guess < secret: 
    print ('Too Low, you scurvy dog!') 
elif guess > secret: 
    print ('Too high, boy') 
    tries = tries + 1 
elif guess == secret: 
    print ('Avast! you got it ! Found my seceret , you did!') 
else: 
    print ('No more guess! Better Luck next time') 
    print ('The secret number was',secret) 

我试过了Python 3.4中的代码。它打印结果超过六次。虽然猜不等于秘密，并尝试... 6次尝试后，它会打印'No more guess better luck next time'，但一次又一次地执行

Answer 1

你有一个缩进问题（我猜是通过粘贴发生的），但你的主要问题是，你是当猜测过高时，只会递增tries。此外，你应该把最后一个动作移出while块，因为while条件已经在处理变量了。

你的实现应该是这样的：

import random 
secret = random.randint(1, 99) 
guess = 0 
tries = 0 
print ('AHOY! I am the Dread Prites Roberts , and i have a secret!') 
print ('It is a number from 1 to 99. I\'ll give you 6 tries ') 

while guess != secret and tries < 6: 
    guess = int(input('What is your guess? ')) 
    tries = tries + 1 
    if guess < secret: 
     print ('Too Low, you scurvy dog!') 
    elif guess > secret: 
     print ('Too high, boy') 

if guess == secret: 
    print ('Avast! you got it ! Found my seceret , you did!') 
else: 
    print ('No more guess! Better Luck next time') 
    print ('The secret number was',secret)