如何在python中获取当前ec2实例的公共ip？

Question

如何在python中获取当前EC2实例的公有ip地址？

Answer 1

import urllib.request 
urllib.request.urlopen("http://169.254.169.254/latest/meta-data/public-ipv4").read() 

Answer 2

如果您已经使用boto，你也可以使用boto.utils.get_instance_metadata功能。这会调用元数据服务器，收集所有元数据并将其作为Python字典返回。它也处理重试。

Answer 3

def console(cmd): 
    p = Popen(cmd,shell=True,stdout=PIPE) 
    out,err = p.communicate() 
    dir_list = out.split('\n') 
    return (dir_list) 
ip = console("http://169.254.169.254/latest/meta-data/public-ipv4") 
print ip 

Answer 4

import requests 
ip = requests.get("http://169.254.169.254/latest/meta-data/public-ipv4").content 

Answer 5

下面的方法将返回公共IP或您的EC2实例的弹性IP地址（注意：如果EIP地址与您的EC2实例相关联，那么公共IP地址实际上是释放）。

这对于Django项目特别有用，因为您可以在settings.py脚本中将IP地址附加到ALLOWED_HOSTS。

• 安装PyCurl

  pip install pycurl 
  

• Python 3中

  import pycurl 
  from io import BytesIO 
  
  # Determine Public IP address of EC2 instance 
  buffer = BytesIO() 
  c = pycurl.Curl() 
  c.setopt(c.URL, 'checkip.amazonaws.com') 
  c.setopt(c.WRITEDATA, buffer) 
  c.perform() 
  c.close() 
  body = buffer.getvalue() 
  # Body is a byte string, encoded. Decode it first. 
  print (body.decode('iso-8859-1').strip()) 
  

• 的Python 2

  import pycurl 
  from StringIO import StringIO 
  
  buffer = StringIO() 
  c = pycurl.Curl() 
  c.setopt(c.URL, 'checkip.amazonaws.com') 
  c.setopt(c.WRITEDATA, buffer) 
  c.perform() 
  c.close() 
  
  body = buffer.getvalue() 
  # Body is a string in some encoding. 
  # In Python 2, we can print it without knowing what the encoding is. 
  print (body) 
  

欢呼。