我想创建一个大学数据库,希望在表中编辑选项,以便用户可以编辑特定的记录。但每次我得到语法错误或解析。这里是下面的链接。希望有人能帮忙。我认为问题就出在这里通过超链接在PHP中传递值
echo '<a href="www.testpage.php">' . $row['RollNo'] . </a>;
<?php
$con=mysqli_connect("localhost","root","")or die("Connection error");
mysqli_select_db($con,"lecture7")or die("dbase error");
$sql="select * from students";
$result=mysqli_query($con,$sql);
echo "<table border=1>
<th>RollNo</th>
<th>Name</th>
<th>class</th>
<th>Update</th>";
while($row=mysqli_fetch_array($result, MYSQLI_ASSOC))
{
echo "<tr>";
echo "<td>";
echo $row['RollNo'];
echo "</td>";
echo "<td>";
echo $row['name'];
echo "</td>";
echo "<td>";
echo $row['class'];
echo "</td>";
echo "<td>";
echo '<a href="www.testpage.php">' . $row['RollNo'] . </a>;
echo "</td>";
echo "<br>";
}
?>
您的代码会导致一个语法错误也是如此。 – Twinfriends
Nop。我已经编辑过了。 –
那么,当我评论它是错误的。不,它会工作:) – Twinfriends