如何将新变量与类中的默认变量进行匹配？

Question

在jQuery中有$ .extend（）函数。这基本上就像匹配默认设置和输入设置一样。那么，我想在PHP中使用类似的技术，但似乎没有类似的功能。所以我想知道：是否有与.extend()类似的功能，但在PHP中？如果不是那么，有什么替代品？

这是一个示例类，以及我目前如何获得此效果。我还添加了一个评论，我怎么会希望这样做：

class TestClass { 
    // These are the default settings: 
    var $settings = array(
     'show' => 10, 
     'phrase' => 'Miley rocks!', 
     'by' => 'Kalle H. Väravas', 
     'version' => '1.0' 
    ); 
    function __construct ($input_settings) { 
     // This is how I would wish to do this: 
     // $this->settings = extend($this->settings, $input_settings); 

     // This is what I want to get rid of: 
     $this->settings['show'] = empty($input_settings['show']) ? $this->settings['show'] : $input_settings['show']; 
     $this->settings['phrase'] = empty($input_settings['phrase']) ? $this->settings['phrase'] : $input_settings['phrase']; 
     $this->settings['by'] = empty($input_settings['by']) ? $this->settings['by'] : $input_settings['by']; 
     $this->settings['version'] = empty($input_settings['version']) ? $this->settings['version'] : $input_settings['version']; 

     // Obviously I cannot do anything neat or dynamical with $input_settings['totally_new'] :/ 
    } 
    function Display() { 
     // For simplifying purposes, lets use Display and not print_r the settings from construct 
     return $this->settings; 
    } 
} 

$new_settings = array(
    'show' => 30, 
    'by' => 'Your name', 
    'totally_new' => 'setting' 
); 

$TC = new TestClass($new_settings); 

echo '<pre>'; print_r($TC->Display()); echo '</pre>'; 

如果您发现，有一个全新的设定：$new_settings['totally_new']。这应该只包含在数组内$this->settings['totally_new']。 PS：以上代码输出this。

Answer 1

尝试使用array_merge php函数。代码：

array_merge($this->settings, $input_settings);