2014-08-31 52 views
2

我正在使用Ebean和Java的play framework 2.3.3。 我有以下型号(我实现getter和setter):Ebean/Play框架关系未更新

@Entity 
public class Follow { 

    @ManyToOne 
    private User follower; 

    @ManyToOne 
    private User followed; 
} 

@Entity 
public class User { 

    @Id 
    @GeneratedValue 
    private long id; 

    @OneToMany(mappedBy = "followed") 
    private Set<Follow> followers; 

    @OneToMany(mappedBy = "follower") 
    private Set<Follow> following; 

    public void addFollowing(Follow f) { following.add(f); } 
    public void addFollower(Follow f) { followers.add(f); } 
} 

,并测试了这种关系,我有:

@Test 
public void userFollowTest() { 
    User a = new User(); 
    User b = new User(); 
    Follow follow = new Follow(a, b); // a follows b 
    a.addFollowing(follow); 
    b.addFollower(follow); 

    Ebean.beginTransaction(); 
    Ebean.save(a); 
    Ebean.save(b); 
    Ebean.save(follow); 
    Ebean.commitTransaction(); 

    Assert.assertEquals("Number of users", 2, User.find.all().size()); 
    Assert.assertEquals("Number of following of user A", 1, User.find.byId(1L).getFollowing().size()); 
    Assert.assertEquals("Number of followers of user B", 1, User.find.byId(2L).getFollowers().size()); 
    Assert.assertEquals("Number of follows", 1, Follow.find.all().size()); 
} 

但这个工程:

Assert.assertEquals("Number of users", 2, User.find.all().size()); 
Assert.assertEquals("Number of following of user A", 1, a.getFollowing().size()); 
Assert.assertEquals("Number of followers of user B", 1, b.getFollowers().size()); 
Assert.assertEquals("Number of follows", 1, Follow.find.all().size()); 
Assert.assertTrue("User a is follower and User b is followed", follow.getFollower().getId() == 1 && 
      follow.getFollowed().getId() == 2); 

问题是,尽管在数据库中创建了用户和后续内容,但第二个和第三个断言失败(这是用户没有任何后续操作)。 我试图先创建用户,然后遵循,但它仍然无法正常工作。

回答

1

已解决。看来解决方案是在实体Follow中创建一个ID字段。 我试图把这两个字段作为id,但Ebean不接受它,所以我最终使用了long类型的id。