我正在尝试我的手在OOP,它最近对我不友好。这里是我的课:OOP - 函数未定义?
class db {
protected $host = "";
protected $dbname = "";
protected $user = "";
protected $pass = "";
function execute($query, $parameters, $usefetch) {
$dsn = "mysql:host=$this->host;dbname=$this->dbname";
$pdo = new PDO($dsn,$this->user,$this->pass);
$pdo->setAttribute(PDO::ATTR_EMULATE_PREPARES, false);
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
try {
$statement = $pdo->prepare($query);
$statement->execute($parameters);
if($usefetch) {
$result = $statement->fetchAll(PDO::FETCH_ASSOC);
return $result;
} else {
return SUCCESS;
}
}
catch(PDOException $ex) { return $ex; }
}
function __get($var) {
return $this->$var;
}
}
当我试图把它定义和调用函数“执行”我得到这个错误:
Fatal error: Uncaught Error: Call to undefined function execute() in /var/www/html/api/classes/sessions.php:49 Stack trace: #0 /var/www/html/index.php(3): require_once() #1 {main} thrown in /var/www/html/api/classes/sessions.php on line 49
这里是我正在试图把它(调试)
$db = new db();
die(var_dump($db.execute("SELECT * FROM sessions", [], true)));
我不明白为什么会出现这个错误。它可以是我的PHP配置? (它不执行,即使我做dbexecute自己的功能,而不是一个对象)
尝试'$ DB->'而不是'$ db.':'$ DB->执行(...亚达,亚达,yada' – Rasclatt
-___________________________-有3个小时的搜索时间 – Hiyper
浪费时间!:D – Rasclatt