2015-10-13 91 views
0

我有以下控制器在我的gui上多次实例化。原因是它有一个tableview被填充不同类型的数据。看起来像这样动态添加上下文菜单项到tableview列

class Controller { 
    @FXML 
    TableView<Map<String, String> myTable; 

    private Manager manager; 

    //Each TableView has different ammount of columns with different names that get dynamically added to the table view using this function 

    public void setUpColumns(List<TableColumn<Map<String, String>, String>> columns){ 
     myTable.getColumns().addAll(columns); 
     addContextMenuToColumnHeaders(); 

    } 

    private addContextMenuToColumnHeaders(){ 
     for (TableColumn<Map<String, String>, ?> tc : myTable.getColumns()){ 
      ContextMenu addToGraphContextMenu = createAddToGraphContextMenu(tc); 
      tc.setContextMenu(addToGraphContextMenu); 
     } 
    } 

    private ContextMenu createAddToGraphContextMenu(TableColumn<Map<String, String> String> tc){ 
     for (MangerHandledObject mHO : manager.getHandledObjects()){ 
      MenuItem menuItem = new MenuItem(mHO.getName()); 
      menuItem.setOnAction(new EventHandler<ActionEvent>(){ 

       @Override 
       public void handle(ActionEvent event){ 
        //I want each menu item to have access to the column that is added to get the name of the column. Even after dynamically adding new menuItems 
        manager.callMethod(tc.getName()); 
       } 
      }); 
     } 
    } 

} 

经理处理的对象不是静态的。所以这些都是经理保存的列表中添加和删除的。我想这

contextMenu.setOnShowing(......) 

,并显示它总是从经理检查列表和之前重新使上下文菜单项。但问题是,执行此操作时,我无法再访问这些列。有什么办法可以绕过这个吗?我是否应该实现自己的上下文菜单以获得列名称的字段?

回答

0

它工作。但我必须在我的上下文菜单上添加至少一个虚拟MenuItem才能显示它。