-2
我有这个表中的SQL Server 2016点快速SQL Server的选择结果作为列名
TestDate TestCode TestResult
2017-08-30 HGB 5.3
2017-09-01 HGB 6.1
2017-09-03 HGB 6.8
2017-09-06 HGB 7.9
2017-09-13 HGB 8.5
2017-08-30 EOS% 48.3
2017-09-01 EOS% 47.1
2017-09-03 EOS% 46.4
2017-09-06 EOS% 47.3
2017-09-13 EOS% 38.9
我需要一个查询返回的结果如下图所示:
TestDate HGB EOS%
2017-08-30 5.3 48.3
2017-09-01 6.1 47.1
2017-09-03 6.8 46.4
2017-09-06 7.9 47.3
2017-09-13 8.5 38.9
这里创建代码&填充表格
Create Table TestResult
(
TestDate Datetime,
TestCode Char(10),
TestResult Char(10)
)
Insert Into TestResult Values('2017/08/30','HGB','5.3')
Insert Into TestResult Values('2017/09/01','HGB','6.1')
Insert Into TestResult Values('2017/09/03','HGB','6.8')
Insert Into TestResult Values('2017/09/06','HGB','7.9')
Insert Into TestResult Values('2017/09/13','HGB','8.5')
Insert Into TestResult Values('2017/08/30','EOS%','48.3')
Insert Into TestResult Values('2017/09/01','EOS%','47.1')
Insert Into TestResult Values('2017/09/03','EOS%','46.4')
Insert Into TestResult Values('2017/09/06','EOS%','47.3')
Insert Into TestResult Values('2017/09/13','EOS%','38.9')
您需要:PIVOT(https://开头的TechNet .microsoft.com/EN-US /库/ ms177410(v = SQL.105)的.aspx) –