如何查询postgres数组在Ruby on Rails整数使用变量？

Question

Notification.where("uip @> ?", '{1}') 

工作正常，并返回其所有UIP阵列包含1

如果我尝试但是具有可变以下，我没有这样的运气通知：

ip = 1 

Notification.where("uip @> ?", '{ip}') 

返回错误：

Notification Load (1.8ms) SELECT "notifications".* FROM "notifications" WHERE (uip @> '{ip}') 
PG::InvalidTextRepresentation: ERROR: invalid input syntax for integer: "ip" 
LINE 1: ...otifications".* FROM "notifications" WHERE (uip @> '{ip}') 
                   ^
: SELECT "notifications".* FROM "notifications" WHERE (uip @> '{ip}') 
ActiveRecord::StatementInvalid: PG::InvalidTextRepresentation: ERROR: invalid input syntax for integer: "ip" 
LINE 1: ...otifications".* FROM "notifications" WHERE (uip @> '{ip}') 
                   ^
: SELECT "notifications".* FROM "notifications" WHERE (uip @> '{ip}') 

而另一尝试用：

Notification.where("uip @> ?", ip) 

给出了错误：

SELECT "notifications".* FROM "notifications" WHERE (uip @> 1) 
PG::UndefinedFunction: ERROR: operator does not exist: bigint[] @> integer 
LINE 1: ...CT "notifications".* FROM "notifications" WHERE (uip @> 1) 
                   ^
HINT: No operator matches the given name and argument type(s). You might need to add explicit type casts. 
: SELECT "notifications".* FROM "notifications" WHERE (uip @> 1) 
ActiveRecord::StatementInvalid: PG::UndefinedFunction: ERROR: operator does not exist: bigint[] @> integer 
LINE 1: ...CT "notifications".* FROM "notifications" WHERE (uip @> 1) 
                   ^
HINT: No operator matches the given name and argument type(s). You might need to add explicit type casts. 
: SELECT "notifications".* FROM "notifications" WHERE (uip @> 1) 

所以，我怎么能简单地找到在轨Postgres的阵列内的整数变量的对象？

谢谢！

Answer 1

有多种方式，你可以在一个Postgres阵列查询使用ActiveRecord：

固定查询：

ip = 1  
Notification.where("uip @> '{?}'", ip) 

使用 '任意'：

ip = 1 
Notification.where("uip && ARRAY[?]", ip) 

Answer 2

使用它。我认为这是有帮助的，你

ip = 1 
Notification.where("uip @> ?", "#{ip.to_s.to_i}") 

OR

Notification.where("uip @>?",ip.to_s.to_i) 

Answer 3

试试这一个。我刚搬到你的括号进入条件：

ip = 1 
Notification.where("uip @> '{?}'", ip) 

Answer 4

您需要从输入中创建一个数组：

Notification.where("uip @> CAST(ARRAY[?] AS BIGINT[])", ip) 
// or 
Notification.where("uip @> CAST(? AS BIGINT[])", '{' + ip.to_s + '}') 
// or 
Notification.where("uip @> CAST('{' || ? || '}' AS BIGINT[])", ip) 

如果您只想测试一个元素，那么也可以使用重叠（&&）运算符（它应该更快一些）。或者，你可以使用数组ANY结构：

Notification.where("? = ANY (uip)", ip)