我有一个使用下面的代码进行加载的问题。急于加载返回的ID而不是型号
问题是与状态模型
$ticket = Ticket::where('id', $id)->with(['customer', 'status', 'notes' => function($query) {
$query->orderBy('updated_at', 'desc');
}])->first();
如果我这样做,
return response()->json($ticket);
我得到预期的回应,一切OK
{"id":1,"customer_id":10001,"ztk_ticket_no":"ZTK0000001","status":{"id":1,"value":"Open","deleted_at":null,"created_at":"2016-02-13 01:36:20","updated_at":"2016-02-13 01:36:20"},"deleted_at":null,"created_at":"2016-02-13 01:36:20","updated_at":"2016-02-13 01:36:20","customer":{"id":1,"customer_id":10001,"title":"Test Company","deleted_at":null,"created_at":"2016-02-13 01:36:20","updated_at":"2016-02-13 01:36:20"},"notes":[{"id":1,"ticket_id":1,"note":"Lorem ipsum dolor sit amet, ","status":1,"deleted_at":null,"created_at":"2016-02-13 01:36:20","updated_at":"2016-02-13 01:36:20"}]}
但如果我这样做
return response()->json($ticket->status);
我得到地位的ID,而不是模型
1
状态型号:
class Status extends Model
{
protected $table = 'statuses';
}
票务型号:
class Ticket extends Model
{
public function status() {
return $this->hasOne('App\Status', 'id', 'status');
}
}
尝试:$ ticket-> status() - > get(); –
你试过这个吗? –
哦,这很有效,谢谢。 任何想法,为什么我必须这样做? – BrendanDodd