允许用户使用BlobstoreService将文件上传并保存到我的GCS桶中，如何识别上传的文件？

请帮助。我试图使用BlobstoreService将视频文件（.mp4）上传到GCS存储桶。允许用户使用BlobstoreService将文件上传并保存到我的GCS桶中，如何识别上传的文件？

该文件已成功上载并自动保存在我的GCS Bucket中，并且客户端接收到值为“YES”的密钥“upload_result”。
问题是我不知道如何识别由BlobstoreService保存在我的存储桶中的上传文件以及如何从请求中获取其他信息，例如'foo'和'bar'键值。

Document说我可以使用BlobInfo＃getGsObjectName（）来获取名称，但似乎该方法现在不可用。
我可以从请求中获得'blobkey'，但我认为它只适用于Blobstore而不适用于GCS。
是的，我可以得到原始文件名，但原来的名称在GCS中丢失，而对象名称是唯一的名称。

com.google.appengine.api.blobstore.BlobInfo https://cloud.google.com/appengine/docs/java/javadoc/com/google/appengine/api/blobstore/BlobInfo.html#getGsObjectName--

///// JSP /////// 
<%! 
final String BUCKT_NAME = "my_bucket"; 
final long MAX_SIZE = 1024 * 1024 * 300; 
String uploadURL; 

BlobstoreService blobstoreService = BlobstoreServiceFactory.getBlobstoreService(); 
UploadOptions uploadOptions = UploadOptions.Builder 
           .withGoogleStorageBucketName(BUCKET_NAME) 
           .maxUploadSizeBytes(MAX_SIZE); 
uploadURL = blobstoreService.createUploadUrl("/handler", uploadOptions); 
%> 


///// HTML Form /////// 
<form id="file_upload_form" action="" method="post" enctype="multipart/form-data"> 
    <input type="file" name="uploaded_file"> 
    <button type="button">UPLOAD</button> 
    <input type="hidden" name="foo" value="bar"> <-- I want to upload additional information with the video file. 
</form> 


///// ajax /////// 

function uploadFile(){ 
    var fd = new FormData($('#file_upload_form').get(0)); 
    $.ajax({ 
     url: "<%=uploadURL %>", 
     type: 'POST', 
     data: fd, 
     processData: false, 
     contentType: false, 
     dataType: 'json' 
    }) 
     .done(function(data) { 
     if(data['upload_result'] == 'YES'){ 
      //Do sometihng 
     } 
     else{ 
      //Do something 
     } 
    }); 
} 

///// SERVLET(Slim3 Controller) (/handler) /////// 

private Navigation doPost() { 
HttpServletRequest httpServletRequest = RequestLocator.get(); 
BlobstoreService blobstoreService = BlobstoreServiceFactory.getBlobstoreService(); 
Map<String, List<BlobKey>> blobs = blobstoreService.getUploads(httpServletRequest); 
List<BlobKey> blobKeys = blobs.get("uploaded_file"); 
BlobKey fileKey = blobKeys.get(0); 
BlobInfoFactory blobInfoFactory = new BlobInfoFactory(); 
BlobInfo blobInfo = blobInfoFactory.loadBlobInfo(fileKey); 

String originalFileName = blobInfo.getFilename(); 
long filesize = blobInfo.getSize(); 
//String gcsObjectName = blobInfo.getGsObjectName(); <<-- Most important thing is not available. 

if(blobKey!=null){ 
    String result = "{\"upload_result\":\"YES\"}"; 
     response.setCharacterEncoding("utf-8"); 
     response.setContentType("application/json"); 
     try { 
      response.getWriter().println(result); 
     } catch (IOException e) { 
      e.printStackTrace(); 
     } 
} 
return null;

编辑。使用FileInfo而不是BlobInfo来获取生成的GCS对象名称。这是这种情况的工作代码。

BlobstoreService blobstoreService = BlobstoreServiceFactory.getBlobstoreService(); 
Map<String, List<FileInfo>> fileInfos = blobstoreService.getFileInfos(request); 
List<FileInfo> infos = fileInfos.get("uploaded_file"); 
FileInfo info = infos.get(0); 
String gcsObjectName = info.getGsObjectName(); // <--

来源

2017-01-31 Ando Katsuya

团块关键是两个GCS和Blob存储的唯一标识符 - 在这里https://cloud.google.com/appengine/docs/java/blobstore/#Java_Using_the_Blobstore_API_with_Google_Cloud_Storage更多细节。对于你使用gcs

BlobstoreService blobstoreService = BlobstoreServiceFactory.getBlobstoreService(); 
BlobKey blobKey = blobstoreService.createGsBlobKey(
    "/gs/" + fileName.getBucketName() + "/" + fileName.getObjectName()); 
blobstoreService.serve(blobKey, resp);

来源

2017-02-01 12:13:20 Aaron

已解决。在这种情况下，我应该在我的处理程序中使用'FileInfo'而不是'BlobInfo'。 –

允许用户使用BlobstoreService将文件上传并保存到我的GCS桶中，如何识别上传的文件？

回答

相关问题