ListView的孩子到新的意图

Question

我跟着一个教程，并有一个可扩展的ListView，并希望链接到一个新的活动的孩子 - 我将如何去做到这一点？我是新来的Android所以任何帮助，将不胜感激:)

createGroupList(); 

    createCollection(); 

    expListView = (ExpandableListView) findViewById(R.id.search_list); 
    final ExpandableListAdapter expListAdapter = new ExpandableListAdapter(
      this, groupList, advSearchOption); 
    expListView.setAdapter(expListAdapter); 

    expListView.setOnChildClickListener(new ExpandableListView.OnChildClickListener() { 

     public boolean onChildClick(ExpandableListView parent, View v, 
            int groupPosition, int childPosition, long id) { 
      final String selected = (String) expListAdapter.getChild(
        groupPosition, childPosition); 
      Toast.makeText(getBaseContext(), selected, Toast.LENGTH_LONG) 
        .show(); 

      return true; 
     } 
    }); 
private void createGroupList() { 
    groupList = new ArrayList<String>(); 
    groupList.add("Advanced Search"); 
} 
private void createCollection() { 
    // preparing laptops collection(child) 
    String[] searches = { "Height", "Weight", 
      "Hair Colour" }; 
    advSearchOption = new LinkedHashMap<String, List<String>>(); 

    for (String advSearch : groupList) { 
     if (advSearch.equals("Advanced Search")) { 
      loadChild(searches); 
     } 

     advSearchOption.put(advSearch, childList); 
    } 
} 
private void loadChild(String[] searchOptions) { 
    childList = new ArrayList<String>(); 
    for (String model : searchOptions) 
     childList.add(model); 
} 

Answer 1

你必须在这里使用意图是在Android的意图的文档：

http://developer.android.com/guide/components/intents-filters.html

但基本上，你在那里有你不得不这样做的吐司：

Intent childIntent = new Intent(this, ChildActivity.class); 
startActivity(childIntent); 

Answer 2

要发送数据到新的Activity.You可以写这样的事情

Intent childIntent = new Intent(this, ChildActivity.class); 
childIntent.putExtra("bind_value", (String) expListAdapter.getChild(
        groupPosition, childPosition)); 
startActivity(childIntent); 

并检索新Activity的onCreate（）中的值。