我在动态添加TextViews时遇到了问题。我想首先通过方法getRoomList()
从列表中添加租用的房间,然后添加带有文本“:Free”的房间,这些房间位于existingRoomNames
阵列中,但未被雇佣。将多个TextViews动态添加到LinearLayout中
public void checkRoomsAndDate() {
linearLayout = (LinearLayout) findViewById(R.id.linear1);
linearLayout.removeAllViews();
for (Room room : mCalendarModel.mList.getRoomList()) {
addHiredRoomToLayout(room);
}
addNotHiredRoomsToLayout();
}
public void addHiredRoomToLayout(Room room) {
textView = new TextView(this);
textView.setText(room.getParameters());
linearLayout.addView(textView);
}
public void addNotHiredRoomsToLayout() {
textView2 = new TextView(this);
for (String name : Constants.existingRoomNames) {
boolean contains = false;
for (Room room : mCalendarModel.mList.getRoomList()) {
if (room.getName().equals(name)) {
contains = true;
}
}
if (!contains) {
textView2.setText(name + ": Free");
linearLayout.addView(textView2);
}
}
}
这里的XML:
<LinearLayout
android:orientation="vertical"
android:layout_width="313dp"
android:layout_height="150dp"
android:id="@+id/linear1"
android:layout_gravity="center"></LinearLayout>
这是父的LinearLayout内。
我得到的例外是这样的:
`java.lang.IllegalStateException: The specified child already has a parent. You must call removeView() on the child's parent first.`
在最后一行:
linearLayout.addView(textView2);
什么问题呢?
如果解决了您的问题,请将答案标记为已接受。 –
解决了,谢谢你! –