2016-07-22 69 views
1

我在动态添加TextViews时遇到了问题。我想首先通过方法getRoomList()从列表中添加租用的房间,然后添加带有文本“:Free”的房间,这些房间位于existingRoomNames阵列中,但未被雇佣。将多个TextViews动态添加到LinearLayout中

public void checkRoomsAndDate() { 
    linearLayout = (LinearLayout) findViewById(R.id.linear1); 
    linearLayout.removeAllViews(); 
    for (Room room : mCalendarModel.mList.getRoomList()) { 
     addHiredRoomToLayout(room); 
    } 
    addNotHiredRoomsToLayout(); 
} 

public void addHiredRoomToLayout(Room room) { 
    textView = new TextView(this); 
    textView.setText(room.getParameters()); 
    linearLayout.addView(textView); 
} 

public void addNotHiredRoomsToLayout() { 
    textView2 = new TextView(this); 
    for (String name : Constants.existingRoomNames) { 
     boolean contains = false; 
     for (Room room : mCalendarModel.mList.getRoomList()) { 
      if (room.getName().equals(name)) { 
       contains = true; 
      } 
     } 
     if (!contains) { 
      textView2.setText(name + ": Free"); 
      linearLayout.addView(textView2); 
     } 
    } 
} 

这里的XML:

<LinearLayout 
    android:orientation="vertical" 
    android:layout_width="313dp" 
    android:layout_height="150dp" 
    android:id="@+id/linear1" 
    android:layout_gravity="center"></LinearLayout> 

这是父的LinearLayout内。

我得到的例外是这样的:

`java.lang.IllegalStateException: The specified child already has a parent. You must call removeView() on the child's parent first.` 

在最后一行:

linearLayout.addView(textView2); 

什么问题呢?

回答

2

你又增加了布局同样的观点。 将您的功能更改为

public void addNotHiredRoomsToLayout() { 

for (String name : Constants.existingRoomNames) { 
    textView2 = new TextView(this); 
    boolean contains = false; 
    for (Room room : mCalendarModel.mList.getRoomList()) { 
     if (room.getName().equals(name)) { 
      contains = true; 
     } 
    } 
    if (!contains) { 
     textView2.setText(name + ": Free"); 
     linearLayout.addView(textView2); 
    } 
} 
} 
+0

如果解决了您的问题,请将答案标记为已接受。 –

+0

解决了,谢谢你! –

1

移动

linearLayout = (LinearLayout) findViewById(R.id.linear1); 
linearLayout.removeAllViews(); 

public void addHiredRoomToLayout(Room room) { 
    textView = new TextView(this); 
    textView.setText(room.getParameters()); 
    linearLayout.addView(textView); 
} 
1

问题是您每次都使用相同的TextView。 如果你想使用多个TextViews那么你的循环改为

for (String name : Constants.existingRoomNames) { 
    textView2 = new TextView(this); //create a new TextView that wasn't added to layout yet 

    boolean contains = false; 
    for (Room room : mCalendarModel.mList.getRoomList()) { 
     if (room.getName().equals(name)) { 
      contains = true; 
     } 
    } 
    if (!contains) { 
     textView2.setText(name + ": Free"); 
     linearLayout.addView(textView2); 
    } 
} 
0

请试试这个 - >进行命名的一个XML布局文件“text_view”:

<TextView xmlns:android="http://schemas.android.com/apk/res/android" 
    android:layout_height="wrap_content" 
    android:layout_width="wrap_content"/> 

再行解决这个问题:

textView2 = (TextView) getLayoutInflater().inflate(R.layout.text_view, null); 
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