我有一些web方法将我的对象作为序列化的XML返回。它只是序列化对象的NHibernate映射的属性......任何人都有一些洞察力?这似乎是网络方法实际上序列化NHibernate代理而不是我的类。我试过使用[XMLInclude]和[XMLElement],但属性仍然没有序列化。我有一个非常可怕的解决方法,但我想知道是否有更好的方法!如何序列化NHibernate映射对象的所有属性?
事情是这样的:
<?xml version="1.0" ?>
<hibernate-mapping xmlns="urn:nhibernate-mapping-2.2" namespace="StoryManager" assembly="StoryManager">
<class name="Graphic" table="graphics" lazy="false">
<id name="Id" column="id" type="int" unsaved-value="0" >
<generator class="identity"/>
</id>
<property name="Assigned" />
<property name="Due" />
<property name="Completed" />
<property name="UglyHack" insert="false" update="false" />
<many-to-one name="Parent" class="Story" column="story_id"/>
</class>
</hibernate-mapping>
public class Graphic
{
private int m_id;
public virtual int Id
{
get { return m_id; }
set { m_id = value; }
}
private DateTime? m_assigned;
public virtual DateTime? Assigned
{
get { return m_assigned; }
set { m_assigned = value; }
}
private DateTime? m_due;
public virtual DateTime? Due
{
get { return m_due; }
set { m_due = value; }
}
private DateTime? m_completed;
public virtual DateTime? Completed
{
get { return m_completed; }
set { m_completed = value; }
}
public bool UglyHack
{
get { return m_due < m_completed; } // return something besides a real mapped variable
set {} // trick NHibernate into thinking it's doing something
}
}
这显然是没有办法写代码。如果我没有那里的“假”映射(UglyHack属性),那么该属性将不会被序列化。现在我正在考虑使用(数据)传输对象,并可能会使用反射...
请发表一个小例子。 – 2009-07-27 23:24:35