MYSQL计数次数值在3列中的次数

Question

我有一个查询获取有关客户的一些数据。这个客户可以有三个电话号码，这些可以重复。

要计算的次数，这些手机都是重复的合作伙伴已创建一个子查询：

(select count(*) 
from TABLE_A as k 
where (k.phone=a.phone or k.phone2=a.phone or k.phone3=a.phone) 
and k.id!=a.id) as repetitionsPhone1 

这里面一个更大的选择是这样的：

SELECT a.*,c.*,b.*, 
    (
     select count(*) 
     from TABLE_A as k 
     where (k.phone=a.phone or k.phone2=a.phone or k.phone3=a.phone) 
     and k.id!=a.id 
    ) as repetitionsPhone1 
    FROM a 
    left join c on a.id=c.id 
    left join b on a.id=b.id 

此查询时间为50行约30秒，每天应该返回约2000行。

优化这个我用explain，我看到那么我搜索，我想这该子查询是问题：

SELECT phn,sum(count) as phoneRepetitions 
from (
    select k.phone1 as phn, count(*) as count 
    from k 
    group by k.phone1 
     UNION 
    select k.phone2 as phn,count(*) as count 
    from k 
    group by k.phone2 
     UNION 
    select k.phone3 as phn,count(*) as count 
    from k 
    group by k.phone3 
) as aux 
    group by phn 

这将返回#1062 MYSQL error: Duplicate entry for key 'distinct key'

首先，我想解决的这个问题。任何人都知道发生了什么？这个错误在插入语句中似乎是逻辑的，但在选择？

然后，这将有助于改善我必须优化的大选择吗？我将不得不为三列进行此操作。

谢谢。

Answer 1

SELECT count(*) from 

    (SELECT phones1 FROM k 
    union 
    SELECT phones2 from k 
    union 
    SELECT phones3 from k) 

AS SumCountPhones 

这似乎适用于我。
解决方案按照How do I add two count(*) results together on two different tables?

您可以继续堆叠工会。

Answer 2

SELECT 
COUNT(*) AS CountOf FROM 
    table1 
    INNER JOIN 
table2 
GROUP BY phone1 , phone2 , phone3 
HAVING COUNT(*) > 1