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我想要下面的代码在customer_payment表中插入汽车ID,但它只选择477 ID。我不知道为什么。如图所示,只有product_id 477被插入,如果我选择500,它仍然会插入477.请帮助我获得此帮助。谢谢 为什么正确的ID没有插入表
include 'admin/db.php';
if(isset($_GET['payment_here'])){
//select product id from cart
$select_cart = "select * from cart";
$runcart = mysqli_query($conn, $select_cart);
$cartwhile=mysqli_fetch_assoc($runcart);
$carssid = $cartwhile['P_ID'];
$cusid = $cartwhile['C_ID'];
//select id from cars
$scars = "select * from cars where id=$carssid";
$scarsrun = mysqli_query($conn, $scars);
$showcars = mysqli_fetch_assoc($scarsrun);
$carsdealer = $showcars['dealer'];
//select customer id from customer table
//$selectcust = "select * from customer_register where id=$cusid";
//insert data into customer payment table
echo $insertpay = "insert into customer_payment
(Product_id, customer_id, dealer)
values ($carssid," . $_SESSION['customer_id'] . ", '$carsdealer')";
$run_inserts = mysqli_query($conn, $insertpay);
/*
if($run_inserts){
echo "<script>window.location.href = 'checkout.php'</script>";
}
*/
}
?>
它确实输入了登录的客户ID,如图3所示。这很好,问题出在product_id上,为什么它只选择了477个产品ID。 –
,因为购物车表中的**第一个条目**必须将customer_id设为477. – nikamanish
您正在从当前会话插入**客户ID,但您没有根据当前customer_id获取**数据。 – nikamanish