递归层次查询到xml

Question

要使用dynatree（https://code.google.com/p/dynatree/）我希望结果在下面的xml表单中，但结果不是我想要的。 dynatree请求第二个组织树。

有人可以帮我吗？

SELECT 
    XMLELEMENT("div",xmlattributes('tree' AS "id"), 
     (SELECT DBMS_XMLGEN.getXMLType(
    DBMS_XMLGEN.newContextFromHierarchy(' 
     SELECT LEVEL, 
      case 
      when CONNECT_BY_ISLEAF = 0 then 
       XMLELEMENT("ul", XMLELEMENT("li", xmlattributes(empno AS "id"), ename)) 
      when CONNECT_BY_ISLEAF = 1 then 
       XMLELEMENT("li", xmlattributes(empno AS "id"), ename) 
      end 
      FROM emp 
     START WITH mgr is null 
     CONNECT BY PRIOR empno = mgr ' 
     ) 
     ) FROM DUAL 
    )) XMLDOC 
FROM DUAL; 

当前结果

<div id="tree"><ul> 
    <li id="7839">KING</li> 
    <ul> 
    <li id="7566">JONES</li> 
    <ul> 
     <li id="7788">SCOTT</li> 
     <li id="7876">ADAMS</li> 
    </ul> 
    <ul> 
     <li id="7902">FORD</li> 
     <li id="7369">SMITH</li> 
    </ul> 
    </ul> 
    <ul> 
    <li id="7698">BLAKE</li> 
    <li id="7499">ALLEN</li> 
    <li id="7521">WARD</li> 
    <li id="7654">MARTIN</li> 
    <li id="7844">TURNER</li> 
    <li id="7900">JAMES</li> 
    </ul> 
    <ul> 
    <li id="7782">CLARK</li> 
    <li id="7934">MILLER</li> 
    </ul> 
</ul> 
</div> 

期望的结果

<ul> 
    <li id="7839">KING 
    <ul> 
    <li id="7566">JONES 
    <ul> 
     <li id="7788">SCOTT 
     <ul> 
     <li id="7876">ADAMS</li> 
     </ul> 
     </li> 
     <li id="7902">FORD 
     <ul> 
     <li id="7369">SMITH</li> 
     </ul> 
     </li> 
    </ul> 
    </li> 
    <li id="7698">BLAKE 
    <ul> 
     <li id="7499">ALLEN</li> 
     <li id="7521">WARD</li> 
     <li id="7654">MARTIN</li> 
     <li id="7844">TURNER</li> 
     <li id="7900">JAMES</li> 
    </ul> 
    </li> 
    <li id="7782">CLARK 
    <ul> 
     <li id="7934">MILLER</li> 
    </ul> 
    </li> 
    </ul> 
    </li> 
</ul> 

SQL脚本如下。

CREATE TABLE EMP 
     (EMPNO NUMBER(4) NOT NULL, 
     ENAME VARCHAR2(10), 
     JOB VARCHAR2(9), 
     MGR NUMBER(4), 
     HIREDATE DATE, 
     SAL NUMBER(7, 2), 
     COMM NUMBER(7, 2), 
     DEPTNO NUMBER(2)); 

INSERT INTO EMP VALUES 
     (7369, 'SMITH', 'CLERK',  7902, 
     TO_DATE('17-12-1980', 'DD-MM-YYYY'), 800, NULL, 20); 

INSERT INTO EMP VALUES 
     (7499, 'ALLEN', 'SALESMAN', 7698, 
     TO_DATE('20-02-1981', 'DD-MM-YYYY'), 1600, 300, 30); 

INSERT INTO EMP VALUES 
     (7521, 'WARD', 'SALESMAN', 7698, 
     TO_DATE('22-02-1981', 'DD-MM-YYYY'), 1250, 500, 30); 

INSERT INTO EMP VALUES 
     (7566, 'JONES', 'MANAGER', 7839, 
     TO_DATE('02-04-1981', 'DD-MM-YYYY'), 2975, NULL, 20); 

INSERT INTO EMP VALUES 
     (7654, 'MARTIN', 'SALESMAN', 7698, 
     TO_DATE('28-09-1981', 'DD-MM-YYYY'), 1250, 1400, 30); 

INSERT INTO EMP VALUES 
     (7698, 'BLAKE', 'MANAGER', 7839, 
     TO_DATE('01-05-1981', 'DD-MM-YYYY'), 2850, NULL, 30); 

INSERT INTO EMP VALUES 
     (7782, 'CLARK', 'MANAGER', 7839, 
     TO_DATE('09-06-1981', 'DD-MM-YYYY'), 2450, NULL, 10); 

INSERT INTO EMP VALUES 
     (7788, 'SCOTT', 'ANALYST', 7566, 
     TO_DATE('09-12-1982', 'DD-MM-YYYY'), 3000, NULL, 20); 

INSERT INTO EMP VALUES 
     (7839, 'KING', 'PRESIDENT', NULL, 
     TO_DATE('17-11-1981', 'DD-MM-YYYY'), 5000, NULL, 10); 

INSERT INTO EMP VALUES 
     (7844, 'TURNER', 'SALESMAN', 7698, 
     TO_DATE('08-09-1981', 'DD-MM-YYYY'), 1500, NULL, 30); 

INSERT INTO EMP VALUES 
     (7876, 'ADAMS', 'CLERK',  7788, 
     TO_DATE('12-01-1983', 'DD-MM-YYYY'), 1100, NULL, 20); 

INSERT INTO EMP VALUES 
     (7900, 'JAMES', 'CLERK',  7698, 
     TO_DATE('03-12-1981', 'DD-MM-YYYY'), 950, NULL, 30); 

INSERT INTO EMP VALUES 
     (7902, 'FORD', 'ANALYST', 7566, 
     TO_DATE('03-12-1981', 'DD-MM-YYYY'), 3000, NULL, 20); 

INSERT INTO EMP VALUES 
     (7934, 'MILLER', 'CLERK',  7782, 
     TO_DATE('23-01-1982', 'DD-MM-YYYY'), 1300, NULL, 10); 

Answer 1

嗨扭转你的情况下的逻辑，我测试了一下，发现这是工作

SELECT 
-- XMLELEMENT("ul",null, 
     (SELECT DBMS_XMLGEN.getXMLType(
    DBMS_XMLGEN.newContextFromHierarchy(' 
     SELECT LEVEL, 
      case 
      when CONNECT_BY_ISLEAF = 1 then 
       XMLELEMENT("ul", XMLELEMENT("li", xmlattributes(empno AS "id"), ename)) 
      when CONNECT_BY_ISLEAF = 0 then 
       XMLELEMENT("ul", XMLELEMENT("li", xmlattributes(empno AS "id"), ename), null) 
      end 
      FROM emp 
     START WITH mgr is null 
     CONNECT BY PRIOR empno = mgr ' 
     ) 
     ) FROM DUAL 
    ) 
--  ) XMLDOC 
FROM DUAL; 

请检查出来把你需要的是完全一样ü在问题中指定。

按照我出去放应该像如下：

<ul> 
    <li id="7839">KING</li> 
    <ul> 
    <li id="7566">JONES</li> 
    <ul> 
     <li id="7788">SCOTT</li> 
     <ul> 
     <li id="7876">ADAMS</li> 
     </ul> 
    </ul> 
    <ul> 
     <li id="7902">FORD</li> 
     <ul> 
     <li id="7369">SMITH</li> 
     </ul> 
    </ul> 
    </ul> 
    <ul> 
    <li id="7698">BLAKE</li> 
    <ul> 
     <li id="7499">ALLEN</li> 
    </ul> 
    <ul> 
     <li id="7521">WARD</li> 
    </ul> 
    <ul> 
     <li id="7654">MARTIN</li> 
    </ul> 
    <ul> 
     <li id="7844">TURNER</li> 
    </ul> 
    <ul> 
     <li id="7900">JAMES</li> 
    </ul> 
    </ul> 
    <ul> 
    <li id="7782">CLARK</li> 
    <ul> 
     <li id="7934">MILLER</li> 
    </ul> 
    </ul> 
</ul> 

检查和更新，如果这是你所需要的。