复制指定的子节点从一个XML文件到另一个XML文件在C＃

Question

下面是我的两个XML文件 - 示例XML文件

<tbltemp> 
 
    <Details> 
 
    <Id>1</Id> 
 
    <Name>John</Name> 
 
    <Date>25.09.2016</Date> 
 
    <Time>09:30:45</Time> 
 
    <Flag>1</Flag> 
 
</Details> 
 
<Details> 
 
    <Id>2</Id> 
 
    <Name>John</Name> 
 
    <Date>25.09.2016</Date> 
 
    <Time>01:30:45</Time> 
 
    <Flag>1</Flag> 
 
</Details> 
 
<Details> 
 
    <Id>3</Id> 
 
    <Name>John</Name> 
 
    <Date>25.09.2016</Date> 
 
    <Time>11:36:45</Time> 
 
    <Flag>1</Flag> 
 
    </Details> 
 
<Details> 
 
    <Id>1</Id> 
 
    <Name>Jack</Name> 
 
    <Date>25.09.2016</Date> 
 
    <Time>11:36:45</Time> 
 
    <Flag>1</Flag> 
 
</Details> 
 
</tbltemp>

DBfile.xml

<tbltemp> 
 
    <Data> 
 
    <Id>1</Id> 
 
    <Name>John</Name> 
 
    <Age>23</Age> 
 
    <Team>Software</Team> 
 
    <Flag>1</Flag> 
 
    </Data> 
 
    <Data> 
 
    <Id>2</Id> 
 
    <Name>John</Name> 
 
    <Age>23</Age> 
 
    <Team>Software</Team> 
 
    <Flag>1</Flag> 
 
    </Data> 
 
    <Data> 
 
    <Id>3</Id> 
 
    <Name>John</Name> 
 
    <Age>23</Age> 
 
    <Team>Software</Team> 
 
    <Flag>1</Flag> 
 
    </Data> 
 
    <Data> 
 
    <Id>1</Id> 
 
    <Name>Jack</Name> 
 
    <Age>24</Age> 
 
    <Team>Software</Team> 
 
    <Flag>1</Flag> 
 
    </Data> 
 
</tbltemp>

我想从样本XML文件中DBfile.xml要复制的文件的日期和时间，其中的ID匹配两者的XML文件。

我要像这 -

<tbltemp> 
 
    <Data> 
 
    <Id>1</Id> 
 
    <Name>John</Name> 
 
    <Age>23</Age> 
 
    <Team>Software</Team> 
 
    <Date>25.09.2016</Date> 
 
    <Time>09:30:45</Time> 
 
    <Flag>1</Flag> 
 
    </Data> 
 
    <Data> 
 
    <Id>2</Id> 
 
    <Name>John</Name> 
 
    <Age>23</Age> 
 
    <Team>Software</Team> 
 
    <Date>25.09.2016</Date> 
 
    <Time>01:30:45</Time> 
 
    <Flag>1</Flag> 
 
    </Data> 
 
    <Data> 
 
    <Id>3</Id> 
 
    <Name>John</Name> 
 
    <Age>23</Age> 
 
    <Team>Software</Team> 
 
    <Date>25.09.2016</Date> 
 
    <Time>11:36:45</Time> 
 
    <Flag>1</Flag> 
 
    </Data> 
 
    <Data> 
 
    <Id>1</Id> 
 
    <Name>Jack</Name> 
 
    <Age>24</Age> 
 
    <Team>Software</Team> 
 
    <Date>25.09.2016</Date> 
 
    <Time>11:36:45</Time> 
 
    <Flag>1</Flag> 
 
    </Data> 
 
</tbltemp>

的DBfile.xml我一直在使用这样的代码

strDetails = "sample.xml"; 
    strDBDir = "DBfile.xml"; 
var xDoc1 = XDocument.Load(strDetails); 
    var xDoc2 = XDocument.Load(strDBDir); 

    var doc1Entries = xDoc1.Descendants("Details"); 

/// var cloneEntries = doc1Entries.Select(x => new XElement(x));//"AgentId").Value == AgentId.ToString() 
         var cloneEntries = doc1Entries.Select(x => new XElement(x)); 
         xDoc2.Descendants("Date").Last().AddFirst(cloneEntries); 
         xDoc2.Descendants("Time").Last().AddAfterSelf(cloneEntries); 

         xDoc2.Save(strDBDir); 

但无法将数据从一个文件到其他复制。相反，它只是将loginid添加到DBfile.xml中

任何人都可以在这里指导。

Answer 1

使用LINQ加入

using System; 
using System.Collections.Generic; 
using System.Linq; 
using System.Text; 
using System.Xml; 
using System.Xml.Linq; 

namespace ConsoleApplication1 
{ 
    class Program 
    { 
     static void Main(string[] args) 
     { 
      XDocument sampleDoc = XDocument.Load(@"c:\temp\sample.xml"); 
      XDocument dbDoc = XDocument.Load(@"c:\temp\dbfile.xml"); 

      var merge = 
        (from db in dbDoc.Descendants("Data") 
        join sample in sampleDoc.Descendants("Details") on new { id = (int)db.Element("Id"), name = (string)db.Element("Name") } equals new { id = (int)sample.Element("Id"), name = (string)sample.Element("Name") } 
        select new { db = db, sample = sample }); 

      foreach (var row in merge) 
      { 
       row.db.Add(new object[] { 
        row.sample.Element("Date"), 
        row.sample.Element("Time") 
       }); 
      } 

     } 
    } 
}