如何基于从哈希深嵌套数组键值合并哈希阵列

Question

我有这样

@info = [ 
    {"id"=>22014, "act"=>[{"data"=>["show", "video", "audio"], "stud_id"=>11318}]}, 
    {"id"=>22014, "act"=>[{"data"=>["play", "pause", "start"], "stud_id"=>11439}]}, 
    {"id"=>22025, "data"=>[{"data"=>["music"], "stud_id"=>11451}]}, 
    {"id"=>22078, "data"=>[{"data"=>["radio"], "stud_id"=>11705}]}, 
    {"id"=>22050, "act"=>[{"data"=>["switchon", "switchoff", "flatmusic"], "stud_id"=>11099}]} 
] 

一个数组，我想从上面的阵列

@info = [ 
    {"id"=>22014, "act"=>[{"data"=>["show", "video", "audio"], "stud_id"=>11318}, {"data"=>["play", "pause", "start"], "stud_id"=>11439}]}, 
    {"id"=>22025, "data"=>[{"data"=>["music"], "stud_id"=>11451}]}, 
    {"id"=>22078, "data"=>[{"data"=>["radio"], "stud_id"=>11705}]}, 
    {"id"=>22050, "act"=>[{"data"=>["switchon", "switchoff", "flatmusic"], "stud_id"=>11099}]} 
] 

像这样的数组我怎样才能合并这个基于公共ID值？

Answer 1

这是非常基本的Ruby。我留给你not ids_act && h_act的情况。

info = [ 
    {"id"=>22014, "act"=>[{"data"=>["show", "video", "audio"], "stud_id"=>11318}]}, 
    {"id"=>22014, "act"=>[{"data"=>["play", "pause", "start"], "stud_id"=>11439}]}, 
    {"id"=>22025, "data"=>[{"data"=>["music"], "stud_id"=>11451}]}, 
    {"id"=>22078, "data"=>[{"data"=>["radio"], "stud_id"=>11705}]}, 
    {"id"=>22050, "act"=>[{"data"=>["switchon", "switchoff", "flatmusic"], "stud_id"=>11099}]} 
] 

ids = {} 

info.each do | h | 
    puts "h=#{h}" 
    h_id  = h["id"] 
    id_found = ids[h_id] # nil or previously encountered id 
    puts "id_found=#{id_found.inspect}" 

    if id_found 
    then # concatenate act content 
     h_act = h["act"] 
     ids_act = id_found["act"] 
     ids_act = ids_act.concat(h_act) if ids_act && h_act 
    else # store the current hash 
     ids[h_id] = h 
    end 
end 

new_info = ids.collect{ | k, v | v } 
puts '--- new_info ---' 
puts new_info 

执行：

$ ruby -w t.rb 
h={"id"=>22014, "act"=>[{"data"=>["show", "video", "audio"], "stud_id"=>11318}]} 
id_found=nil 
h={"id"=>22014, "act"=>[{"data"=>["play", "pause", "start"], "stud_id"=>11439}]} 
id_found={"id"=>22014, "act"=>[{"data"=>["show", "video", "audio"], "stud_id"=>11318}]} 
h={"id"=>22025, "data"=>[{"data"=>["music"], "stud_id"=>11451}]} 
id_found=nil 
h={"id"=>22078, "data"=>[{"data"=>["radio"], "stud_id"=>11705}]} 
id_found=nil 
h={"id"=>22050, "act"=>[{"data"=>["switchon", "switchoff", "flatmusic"], "stud_id"=>11099}]} 
id_found=nil 
--- new_info --- 
{"id"=>22014, "act"=>[{"data"=>["show", "video", "audio"], "stud_id"=>11318}, {"data"=>["play", "pause", "start"], "stud_id"=>11439}]} 
{"id"=>22025, "data"=>[{"data"=>["music"], "stud_id"=>11451}]} 
{"id"=>22078, "data"=>[{"data"=>["radio"], "stud_id"=>11705}]} 
{"id"=>22050, "act"=>[{"data"=>["switchon", "switchoff", "flatmusic"], "stud_id"=>11099}]} 

Answer 2

info = [ 
    {"id"=>22014, "act"=>[{"data"=>["show", "video", "audio"], "stud_id"=>11318}]}, 
    {"id"=>22014, "act"=>[{"data"=>["play", "pause", "start"], "stud_id"=>11439}]}, 
    {"id"=>22025, "act"=>[{"data"=>["music"], "stud_id"=>11451}]}, 
    {"id"=>22078, "act"=>[{"data"=>["radio"], "stud_id"=>11705}]}, 
    {"id"=>22050, "act"=>[{"data"=>["switchon", "switchoff", "flatmusic"], "stud_id"=>11099}]} 
] 

def combine(info) 
    info.group_by {|g|g["id"]}.values.map {|a| {"id" => a.first["id"], "act"=>a.map {|g| g["act"]}}} 
end 

combine info 

output 

[{"id"=>22014, "act"=>[[{"data"=>["show", "video", "audio"], "stud_id"=>11318}], [{"data"=>["play", "pause", "start"], "stud_id"=>11439}]]}, 
{"id"=>22025, "act"=>[[{"data"=>["music"], "stud_id"=>11451}]]}, 
{"id"=>22078, "act"=>[[{"data"=>["radio"], "stud_id"=>11705}]]}, 
{"id"=>22050, "act"=>[[{"data"=>["switchon", "switchoff", "flatmusic"], "stud_id"=>11099}]]}]