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我想学习Angular,并且我已经构建了一个闹钟。我给用户一个复选框来选择他们想取消的警报,我把它放在英雄中,然后在this.ui()中使用;存储在我的10cal存储中。如何在Angular中将服务调用到组件中?
但是我的视图在元素被删除后没有改变。我怎么做?
1)我想调用我的函数ui();在我的服务完成发布警报后的组件中。
2)如何递归调用函数?
这里是我的register.component.ts
import { Component, OnInit } from '@angular/core';
import {ValidateService} from '../../services/validate.service';
import {AlarmService} from '../../services/alarm.service';
import {FlashMessagesService} from 'angular2-flash-messages';
import {Router} from '@angular/router';
@Component({
selector: 'app-register',
templateUrl: './register.component.html',
styleUrls: ['./register.component.css']
})
export class RegisterComponent implements OnInit {
hours;
id: String;
timeid: String;
time;
heroes: any[];
name:string;
hero = [1,2,3,4,5].map(id => <any>{id:id, time: new Date(2017,5,id)})
constructor(
private validateService: ValidateService,
private FlashMessage: FlashMessagesService,
private Router: Router,
private AlarmService: AlarmService
) {
}
ngOnInit() {
this.ui();
}
ui(){
setTimeout(() => {
this.heroes = JSON.parse(localStorage.getItem('users'));
console.log(this.heroes);
}, 100);
}
check(e){
console.log(e);
console.log(e.target.checked);
console.log(e.target.value);
let get = JSON.parse(localStorage.getItem('users'));
for(var i= get.length -1 ; i > -1; i--) {
if(get[i].id == e.target.value) {
get.splice(i, 1);
}
}
localStorage.setItem('users', JSON.stringify(get));
console.log(get);
this.ui();
let time = new Date().getTime()
this.AlarmService.setUpAlarms(time);
}
}
这是我的报警服务。
import { Injectable } from '@angular/core';
import {FlashMessagesService} from 'angular2-flash-messages';
@Injectable()
export class AlarmService {
constructor(private FlashMessage: FlashMessagesService) {}
setUpAlarms(time: number){
var storage = JSON.parse(localStorage.getItem('users'));
var alarms = [];
var miliseconds = [];
var eventNow = new Date();
for(var i=0; i < storage.length; i++){
var eventEndTime = storage[i]['hours'];
var flag = storage[i]['flag'];
if (eventEndTime >= new Date()) {
alarms.push(storage[i]);
var duration = eventEndTime.valueOf() - eventNow.valueOf();
miliseconds.push(duration);
miliseconds = miliseconds.sort((a, b) => a - b);
}
}
console.log(miliseconds);
localStorage.setItem('users', JSON.stringify(alarms));
for(var i =0; i< miliseconds.length; i++){
setTimeout(() => {
this.FlashMessage.show('ALARM CLOCK WAKE UP', {cssClass: 'alert-danger', timeout: 10000});
}, miliseconds[i]);
return;
}
}
}
好了,还请你帮我吗?我只需要调用服务中组件中的函数ui()。 –
如果您尝试从服务中调用组件中的方法,那么您的应用程序结构错误。组件可以依赖于服务,但不能以其他方式。您的组件应该订阅服务中的observable,它将在组件完成时向组件推送一个值。查看http://blog.angular-university.io/how-to-build-angular2-apps-using-rxjs-observable-data-services-pitfalls-to-avoid/,了解如何在服务中使用observables – glendaviesnz