我已经使用了相对时间很多功能在PHP但得到不同的结果...帮我问题在PHP相对时间函数
我的功能:
<?php
function pretty_relative_time($time) {
if ($time !== intval($time)) { $time = strtotime($time); }
$d = time() - $time;
if ($time < strtotime(date('Y-m-d 00:00:00')) - 60*60*24*3) {
$format = 'F j';
if (date('Y') !== date('Y', $time)) {
$format .= ", Y";
}
return date($format, $time);
}
if ($d >= 60*60*24) {
$day = 'Yesterday';
if (date('l', time() - 60*60*24) !== date('l', $time)) { $day = date('l', $time); }
return $day . " at " . date('g:ia', $time);
}
if ($d >= 60*60*2) { return intval($d/(60*60)) . " hours ago"; }
if ($d >= 60*60) { return "about an hour ago"; }
if ($d >= 60*2) { return intval($d/60) . " minutes ago"; }
if ($d >= 60) { return "about a minute ago"; }
if ($d >= 2) { return intval($d) . " seconds ago"; }
else {return "Just Now"; }
}
function plural($num) {
if ($num != 1)
return "s";
}
function getRelativeTime($date) {
$diff = time() - strtotime($date);
if ($diff<60)
return $diff . " second" . plural($diff) . " ago";
$diff = round($diff/60);
if ($diff<60)
return $diff . " minute" . plural($diff) . " ago";
$diff = round($diff/60);
if ($diff<24)
return $diff . " hour" . plural($diff) . " ago";
$diff = round($diff/24);
if ($diff<7)
return $diff . " day" . plural($diff) . " ago";
$diff = round($diff/7);
if ($diff<4)
return $diff . " week" . plural($diff) . " ago";
return "on " . date("F j, Y", strtotime($date));
}
echo pretty_relative_time('2012-08-06 8:04:15') ;echo "<br/>";
echo getRelativeTime('2012-08-06 8:04:15');
?>
输出:
刚刚//对于第一功能
-15747秒//对于第二功能
在db中的任何设置?.....我已经使用DATETIME的日期...
更改$ diff = time() - strtotime($ date); TO-> $ diff = time() - $ date; – swapnesh 2012-08-06 03:57:23
比它给“2012年8月6日”不是1小时前..... :( – Mehuldabhi 2012-08-06 03:59:13