2017-02-24 83 views
0

我正在通过“学习python hardway”。我很抱歉,如果这是重复的,但我真的不知道我做错了什么。当我输入小于50的数字时,它告诉我再次尝试,并在第二次调用另一个函数中的字符串。如果我在第二个条目中输入大于50的同一个东西,它会在另一个函数中调用另一个字符串。它会从green_dragon()调用并打印出“两条龙都活着烹饪你并且吃掉你。”感谢您提供的任何见解。我为简单而道歉,哈哈。不得不让我自己“的游戏,我不认为创意呢,哈哈。如果返回错误的答案(python)

def gold_room(): 
    print "You have entered a large room filled with gold." 
    print "How many pieces of this gold are you going to try and take?" 
    choice = raw_input("> ") 
    how_much = int(choice) 
    too_much = False 
    while True: 
     if how_much <= 50 and too_much: 
      print "Nice! you're not too greedy!" 
      print "Enjoy the gold you lucky S.O.B!" 
      exit("Bye!") 

     elif how_much > 50 and not too_much: 
      print "You greedy MFKR!" 
      print "Angered by your greed," 
      print "the dragons roar and scare you into taking less." 

     else: 
      print "Try again!" 
     return how_much 

def green_dragon(): 
    print "You approach the green dragon." 
    print "It looks at you warily." 
    print "What do you do?" 
    wrong_ans = False 
    while True: 
     choice = raw_input("> ") 

     if choice == "yell at dragon" and wrong_ans: 
      dead("The Green Dragon incinerates you with it's fire breath!") 
     elif choice == "approach slowly" and not wrong_ans: 
      print "It shows you its chained collar." 
     elif choice == "remove collar"and not wrong_ans: 
      print "The dragon thanks you by showing you into a new room." 
      gold_room() 
     else: 
      print "Both dragons cook you alive and eat you." 
      exit() 
+0

你永远不会改变'too_much',所以第一个'if'永远不会成功。 – Barmar

+0

在第二个函数中,你永远不会改变'wrong_ans',所以第一个'if'永远不会成功。 – Barmar

+0

这两个变量有什么意义? – Barmar

回答

1
too_much = False 

if <= 50 and too_much 

如果too_much设置为False,为什么你所期望的,如果要计算的表达式为true?它永远不会去if里面内环
移动用户输入以及

编辑:。

要停止while循环:

 too_much = True 
     while too_much: 
      choice = raw_input("> ") 
      how_much = int(choice) 
      if how_much <= 50: 
       print "Nice! you're not too greedy!" 
       print "Enjoy the gold you lucky S.O.B!" 
       too_much = False 
      else: 
       print "You greedy MFKR!" 
       print "Angered by your greed," 
       print "the dragons roar and scare you into taking less." 
+0

我将它改为True它仍然做同样的事情,但现在无法打印出来的字符串。 –

+0

我试图在这些课程中将自己的文字游戏作为练习的一部分 –

+0

没有它,它会在一次运行后停止。我试图让它一直要求输入,直到它小于或等于50 –