我试图插入到数据库使用此代码之前验证自己的状态,但我一直printin “你错过了一个值”。我想请你帮忙解决问题。验证输入的形式在PHP
感谢
<?php
$username = mysql_real_escape_string($_POST['username']);
$pword = mysql_real_escape_string($_POST['passwd']);
$fname = mysql_real_escape_string($_POST['firstname']);
$lname = mysql_real_escape_string($_POST['lastname']);
$email = mysql_real_escape_string($_POST['email']);
$telephone = mysql_real_escape_string($_POST['telephone']);
$ad1 = mysql_real_escape_string($_POST['ad1']);
$ad2 = mysql_real_escape_string($_POST['street']);
$ad3 = mysql_real_escape_string($_POST['town']);
$pcode = mysql_real_escape_string($_POST['pcode']);
if($username == " " || $pword == " " || $fname == " " || $lname == " " || $email == " ")
echo 'You missed a value';
exit();
$con = mysql_connect("localhost","root","");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("people", $con);
//$description = mysql_real_escape_string($_POST[description]);
$pword = md5($pword);
$sql="INSERT INTO members (username, pword, fname, lname, email, telephone, ad1, ad2, ad3, pcode)
VALUES
('$username','$pword','$fname', '$lname', '$email','$telephone','$ad1','$ad2','$ad3','$pcode')";
if (!mysql_query($sql,$con)){
die('Error: ' . mysql_error());
}
echo "1 record added";
mysql_close($con)
?>
正在分配值('='),而不是对它们进行比较(''==)。而且我想你想用空字符串“”“'和空格'”“'来比较。 –
不应该是'$ username ==“”':)? P.S:我以前经常犯这个错误。 –
它似乎没有工作。这一次,即使丢失了一些值,它也会插入数据:( – Julie