当我执行下面的程序时,它获取用户输入的帐户详细信息,然后正确打印,但无法读取opt值(y/n)。它会再次自动调用。当用户输入“n”时,如何让程序退出?关于使用scanf输入的问题
char opt;
do
{
//Getting user input
printf("\n Enter the Account Number:\n ");
scanf("%d",&gAccNo_i);
printf("\n Enter the Account Holder's Name:\n ");
scanf("%s",gCustName_c);
printf("\n Enter the Balance Amount:\n ");
scanf("%f",&gBlncAmt_f);
//Printing the input data.
printf("\n Account Number : %d",gAccNo_i);
printf("\n Customer Name : %s",gCustName_c);
printf("\n Balance Amount : %f",gBlncAmt_f);
printf("\n Do u want to wish to continue?(y/n)");
scanf("%c",&opt);
}while(opt!='n');
这是一次机会作业吗? – 2011-03-05 07:13:19
'opt'在你期望它包含'n'时有什么值? – tgdavies 2011-03-05 07:15:26
开关盒?什么? – quasiverse 2011-03-05 07:15:45