更改图形的x轴值c＃

Question

我对c＃和Visual Studio有点新，我想根据位于其他位置的csv文件的值绘制图形。我在c＃中使用ChartObjects和ChartWizard属性来创建图形。绘制的图应该是我提供的列范围，在Y轴和X轴应该有当前行号（1,2,3,4等）。不过，我的默认图形将X轴作为我csv文件中的第一列。如果我也为X轴指定了一个范围，那么它会正确绘图，但是如何获得当前的行号？

我经历了很多文章和问题，即使在堆栈溢出，但似乎没有帮助。

这里是我的代码片段：

Microsoft.Office.Interop.Excel.Application xlexcel; 
Microsoft.Office.Interop.Excel.Worksheet xlWorkSheet; 

object misValue = System.Reflection.Missing.Value; 
xlexcel = new Microsoft.Office.Interop.Excel.Application(); 

var xlWorkBooks = xlexcel.Workbooks; 

xlexcel.Visible = false; 

xlWorkBooks.OpenText(@"C:\" + processName + ".csv", misValue, misValue, Microsoft.Office.Interop.Excel.XlTextParsingType.xlDelimited,   Microsoft.Office.Interop.Excel.XlTextQualifier.xlTextQualifierNone, misValue, misValue, misValue, misValue, misValue, misValue, misValue, misValue, misValue, misValue, misValue, misValue, misValue); 

// Set Sheet 1 as the sheet you want to work with 
xlWorkSheet = (Microsoft.Office.Interop.Excel.Worksheet)xlWorkBooks[1].Worksheets.get_Item(1); 

xlWorkSheet.Shapes.AddChart(misValue, misValue, misValue, misValue, misValue).Select(); 

//~~> Make it a Line Chart 
     xlexcel.ActiveChart.ApplyCustomType(Microsoft.Office.Interop.Excel.XlChartType.xlLine); 

//~~> Set the data range 
xlexcel.ActiveChart.SetSourceData(xlWorkSheet.Range["E2:E200"]); 
xlexcel.ActiveChart.ChartWizard(misValue, Title: chartName + " (" + processName + ")", CategoryTitle: "Iterations", ValueTitle: processType); 

Microsoft.Office.Interop.Excel.ChartObjects chartObjects =(Microsoft.Office.Interop.Excel.ChartObjects)(xlWorkSheet.ChartObjects(Type.Missing)); 
foreach (Microsoft.Office.Interop.Excel.ChartObject co in chartObjects) 
{ 
    co.Select(); 
    Microsoft.Office.Interop.Excel.Chart chart = (Microsoft.Office.Interop.Excel.Chart)co.Chart; 
    chart.Export(ConfigurationManager.AppSettings.Get("Charts") + "\\ProcessFiles" + @"\" + chartName + " (" + processName + "of" + processType + ")" + ".png", "PNG", false); 
    co.Delete(); 
} 
xlWorkBooks[1].Close(true, misValue, misValue); 
xlexcel.Quit(); 

任何指导，将不胜感激。 谢谢！

Answer 1

我想你的代码，并做了一些修改，我希望这将工作

using Excel = Microsoft.Office.Interop.Excel; 

Excel.Application xlApp; 
Excel.Workbook xlWorkBook; 
Excel.Worksheet xlWorkSheet; 

object misValue = System.Reflection.Missing.Value; 
//string appPath = Path.GetDirectoryName(Application.ExecutablePath); 
string fileName = "" + "YOUR_PATH" + "\\Templates\\myCSV.csv"; 

string processName = "test"; 
xlApp = new Excel.Application(); 
xlWorkBook = xlApp.Workbooks.Open(fileName); 
xlWorkSheet = (Excel.Worksheet)xlWorkBook.Worksheets.get_Item(1); 

xlWorkSheet.Shapes.AddChart(misValue, misValue, misValue, misValue, misValue).Select(); 

//~~> Make it a Line Chart 
      xlApp.ActiveChart.ApplyCustomType(Microsoft.Office.Interop.Excel.XlChartType.xlLine); 

//~~> Set the data range 
xlApp.ActiveChart.SetSourceData(xlWorkSheet.Range["B1:B30"]); 
string chartName = "TEST CHART", processType="TEST TYPE"; 
xlApp.ActiveChart.ChartWizard(misValue, Title: chartName + " (" + processName + ")", CategoryTitle: "Iterations", ValueTitle: processType); 

Excel.ChartObjects chartObjects = (Excel.ChartObjects)(xlWorkSheet.ChartObjects(Type.Missing)); 

foreach (Excel.ChartObject co in chartObjects) 
{ 
    co.Select(); 
    Excel.Chart chart = (Excel.Chart)co.Chart; 
    chart.Export("C:\\YOUR_PATH" + @"\" + chart.Name + ".png", "PNG", false); 
} 

xlWorkBook.Close(true, misValue, misValue); 
xlApp.Quit(); 


xlWorkSheet = null; 
xlWorkBook = null; 
xlApp = null; 
releaseObject(xlWorkBook); 
releaseObject(xlWorkSheet); 
releaseObject(xlApp); 

private void releaseObject(object obj) 
{ 
    try 
    { 
    System.Runtime.InteropServices.Marshal.ReleaseComObject(obj); 
    obj = null; 
    } 
    catch (Exception ex) 
    { 
    obj = null; 
    MessageBox.Show(ex.Message); 
    } 
    finally 
    { 
    GC.Collect(); 
    } 
}