2
我一直在努力通过Reactive Programming with RxJava这本书的例子,该书的目标不是版本1而是2.对无限流的介绍有以下示例(并指出有更好的方法来处理并发):RxJava 2相当于isUnsubscribed
Observable<BigInteger> naturalNumbers = Observable.create(subscriber -> {
Runnabler =() -> {
BigInteger i = ZERO;
while (!subscriber.isUnsubscribed()) {
subscriber.onNext(i);
i = i.add(ONE);
}
};
new Thread(r).start();
});
...
Subscription subscription = naturalNumbers.subscribe(x -> log(x));
/* after some time... */
subscription.unsubscribe();
然而,在RxJava 2,传递给create()
方法lambda表达式是ObservableEmitter
类型的,并且这不具有isUnsubscribed()
方法。我看了一下What's Different in 2.0,同时也搜索了版本库,但是找不到任何这样的方法。
如何在2.0中实现相同的功能?
为如下(注意,使用科特林)编辑,包括解决方案:
val naturalNumbers = Observable.create<BigInteger> { emitter ->
Thread({
var int: BigInteger = BigInteger.ZERO
while (!emitter.isDisposed) {
emitter.onNext(int)
int = int.add(BigInteger.ONE)
}
}).start()
}
val first = naturalNumbers.subscribe { log("First: $it") }
val second = naturalNumbers.subscribe { log("Second: $it") }
Thread.sleep(5)
first.dispose()
Thread.sleep(5)
second.dispose()
太棒了,那就是诀窍。谢谢。 – amb85