2012-01-12 58 views
6

嗨,我得到了以下文件:LXML和XSL文件()函数

merge.py:

from lxml import etree 

xml_input = etree.XML(open('a.xml', 'r').read()) 
xslt_root = etree.XML(open('merge.xsl', 'r').read()) 
transform = etree.XSLT(xslt_root) 
print str(transform(xml_input)) 

merge.xsl:

<xsl:stylesheet version="1.0" 
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> 
    <xsl:template match="/"> 
     <merge> 
     <xsl:copy-of select="."/> 
      <xsl:copy-of select="document('b.xml')"/>   
    </merge> 
    </xsl:template> 

A.XML:

<?xml version="1.0" encoding="ISO-8859-1"?> 
<a> 
<test id="1"/> 
</a> 

b.xml:

<?xml version="1.0" encoding="ISO-8859-1"?> 
<b> 
<test id="2"/> 
</b> 

的4个文件在同一目录下,当我打电话merge.py我得到了错误:

lxml.etree.XSLTApplyError: Cannot resolve URI string://__STRING__XSLT__/b.xml 

任何想法?我做错了什么?

+0

如果我使用,我得到了lxml.etree.XSLTApplyError:无法解析URI文件://b.xml – Seb 2012-01-12 08:33:03

回答

8

您需要注册一个URI解析器。请参阅the documentation

大概是这样的(未经测试):

class FileResolver(etree.Resolver): 
    def resolve(self, url, pubid, context): 
     return self.resolve_filename(url, context) 

parser = etree.XMLParser() 
parser.resolvers.add(FileResolver()) 
xml_input = etree.parse(open('a.xml','r'), parser) 
xslt_root = etree.parse(open('merge.xsl','r'), parser) 
transform = etree.XSLT(xslt_root) 
print str(transform(xml_input)) 
+0

嗨弗朗西斯,谢谢你帮助我。我有一个问题,但如何将输出html保存为html文件? – Christopher 2013-10-11 05:25:49

6

为什么就不能这样做呢?

from lxml import etree 

xml_input = etree.parse("a.xml") 
xslt_root = etree.parse("merge.xsl") 
transform = etree.XSLT(xslt_root) 
print str(transform(xml_input)) 

更简单,不需要解析器。