我希望我能解释我想要做的 - 真的希望有人能够帮助！这里是数组我与PHP：需要根据维中的一个键合并/排序多维数组

(
    [0] => Array 
     (
      [city] => Middletown 
      [state] => OH 
      [freq] => 146.610 
      [pl] => 77.0 
      [call] => W8BLV 
      [distance] => 0.0 
      [notes] => ottel 
     ) 

    [1] => Array 
     (
      [city] => Middletown 
      [state] => OH 
      [freq] => 146.715 
      [pl] => 
      [call] => N8COZ 
      [distance] => 0.0 
      [notes] => ct 
     ) 

    [2] => Array 
     (
      [city] => Middletown 
      [state] => OH 
      [freq] => 147.315 
      [pl] => 77.0 
      [call] => W8JEU 
      [distance] => 0.0 
      [notes] => ottel 
     ) 

    [3] => Array 
     (
      [city] => Middletown 
      [state] => OH 
      [freq] => 443.5370 
      [pl] => 118.8 
      [call] => W8MUM 
      [distance] => 0.0 
      [notes] => oe oe 
     ) 

    [4] => Array 
     (
      [city] => Middletown 
      [state] => OH 
      [freq] => 444.4750 
      [pl] => 100.0 
      [call] => AG8Y 
      [distance] => 0.0 
      [notes] => ottel 
     ) 

    [5] => Array 
     (
      [city] => Middletown 
      [state] => OH 
      [freq] => 444.8250 
      [pl] => 77.0 
      [call] => W8BLV 
      [distance] => 0.0 
      [notes] => oel 
     ) 

    [6] => Array 
     (
      [city] => Monroe 
      [state] => OH 
      [freq] => 443.0870 
      [pl] => 
      [call] => KC8ECK 
      [distance] => 4.3 
      [notes] => oep 
     ) 

    [7] => Array 
     (
      [city] => Franklin 
      [state] => OH 
      [freq] => 145.290 
      [pl] => 118.8 
      [call] => WB8ZVL 
      [distance] => 5.5 
      [notes] => o(ca)r 
     ) 

    [8] => Array 
     (
      [city] => Franklin 
      [state] => OH 
      [freq] => 442.4250 
      [pl] => 77.0 
      [call] => WE8N 
      [distance] => 5.5 
      [notes] => Oae(ca) 
     ) 

    [9] => Array 
     (
      [city] => Franklin 
      [state] => OH 
      [freq] => 443.1500 
      [pl] => 118.8 
      [call] => WB8ZVL 
      [distance] => 5.5 
      [notes] => o(ca)r 
     ) 

    [10] => Array 
     (
      [city] => Springboro 
      [state] => OH 
      [freq] => 145.490 
      [pl] => 77.0 
      [call] => W8CYE 
      [distance] => 8.9 
      [notes] => oe 
     ) 

)

输出工作，我希望得到的需求是这样的：

$rpt[0] ="Middletown 146.61/77, 146.715, 147.315/77, 443.537/118.8, 444.475/100, 444.825/77"; 
$rpt[1] = "Monroe 443.087"; 
$rpt[2] = "Franklin 145.29/118.8, 442.425/77, 443.15/118.8"; 
$rpt[3] = "Springboro 145.49/77"

我最感兴趣的是城市，频率的领域， PL - 如果你看看第一个数组，我已经删除了输出数组上的尾随零。也有几次，当我可能需要使用呼叫字段和笔记字段时，但是如果有人能指向我正确的方向，我可能会计算出我需要的其余部分 - 呼叫字段和笔记字段不会经常使用。我已经尝试了几个不同的foreach循环，但我仍然是PHP的新手 - 而且我所做的工作并不正确，而且我在这点上需要一些帮助。

在此先感谢您的帮助，乐华，KD8BXP

来源

2010-07-21 LeRoy Miller

foreach($input_array as $item) { 
    $output_array[$item['city']][] = array(
      'freq' => $item['freq'], 
      'pl' => $item['pl'] 
     ); 
}

有了这个，$output_array最终将成为一个关联数组，它的键是城市，其值频率+ PL数组列表：

Array 
(
    ["Middletown"] => Array 
     (
      [0] => Array 
       (
        [freq] => 146.610, 
        [pl] => 77.0 
       ), 
      [1] => Array 
       (
        [freq] => 146.715, 
        [pl] => 
       ) 
      // etc... 
     ) 
    // etc... 
)

（而且欢迎您 - 琥珀，KC9HTI）

编辑

一旦你运行上面的代码，你可以使用此代码来获得你想要的最终格式：那么

foreach($output_array as $city => $freq_list) { 
    $freqs = array(); 
    foreach($freq_list as $freq) { 
     $freq_str = $freq['freq']; 
     if($freq['pl']) $freq_str .= "/" . $freq['pl']; 
     $freqs[] = $freq_str; 
    } 
    $rpt[] = $city . " " . implode(", ", $freqs); 
}

$rpt应该有你想要的阵列。

来源

2010-07-21 04:06:22 Amber

琥珀，感谢您的快速答案...不太我所期待的事，但要更接近当时我让我的自己的！我想我可以为你工作。非常感谢你的帮助。 LeRoy，KD8BXP – 2010-07-21 04:14:29

嗯。让我看看我是否可以调整它以更贴近地满足您的需求。 :) – Amber 2010-07-21 04:20:13

看看我添加在底部的位是否有帮助。 – Amber 2010-07-21 04:25:30

这里是你需要的东西：

// Here $items is your input array. 

/* First, sort input array by freq */ 

function compareByFreq($a, $b) 
{ 
    if ($a['freq'] == $b['freq']) { 
     return 0; 
    } 
    return ($a['freq'] < $b['freq']) ? -1 : 1; 
} 

uasort($items, 'compareByFreq'); 



/* Aggregate required data */ 

$result = array(); 
foreach($items as $item) 
{ 
    if (isset($result[$item['city']])) { 
     $result[$item['city']] .= ', '. $item['freq']; 
    } else { 
     $result[$item['city']] = $item['city'] . ' ' . $item['freq']; 
    } 
    if (! empty($item['pl'])) { 
     $result[$item['city']] .= '/' . $item['pl']; 
    } 
} 

$result = array_values($result); // get rid of assoc keys

来源

2010-07-21 04:38:07 Serg

PHP：需要根据维中的一个键合并/排序多维数组

回答

编辑

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