从异步调用返回响应

-2

在开始之前，我已经花了很长时间阅读本： How do I return the response from an asynchronous call?从异步调用返回响应

我有一个硬编码变量，被称为“d”，被定义为一个二维数组：

var d = [ 
    ["05_001","05_002","05_003","05_004","05_005"], 
    ["05_006","05_007","05_008","05_009","05_010"] 
];

我想使用AJAX get，所以我可以从数据库中获取值。

我想这个简单的解决方法：

function foo(callback) { 
    return $.ajax({ 
     url: 'emoji.php?cat=emoticons_activity', 
     success: callback 
    }); 
} 

var result; 
foo(function(response) { 
    result = response; 
    alert(result); 
});

但是，即使我这样做，我仍然停留，因为我还需要设置变量“d”的值是通过返回的值“富“功能。

我需要使用代码这段代码的情况下：

tinymce.PluginManager.add("emoticons_travel_places", function(a, b) { 
    function c() { 
     var a; 
     return a = '<table role="list" class="mce-grid">', tinymce.each(d, function(c) { 
      a += "<tr>", tinymce.each(c, function(c) { 
       var d = b + "/img/" + c + ".svg"; 
       a += '<td><a href="#" data-mce-url="' + d + '" data-mce-alt="' + c + '" tabindex="-1" role="option" aria-label="' + c + '"><img src="' + d + '" style="width:30px; height:30px" role="presentation" /></a></td>' 
      }), a += "</tr>" 
     }), a += "</table>" 
    } 

    var d = [ 
     ["05_001","05_002","05_003","05_004","05_005","05_006","05_007","05_008","05_009","05_010","05_011","05_012","05_013","05_014","05_015","05_016","05_017","05_018","05_019","05_020"], 
     ["05_021","05_022","05_023","05_024","05_025","05_026","05_027","05_028","05_029","05_030","05_031","05_032","05_033","05_034","05_035","05_036","05_037","05_038","05_039","05_040"], 
     ["05_041","05_042","05_043","05_044","05_045","05_046","05_047","05_048","05_049","05_050","05_051","05_052","05_053","05_054","05_055","05_056","05_057","05_058","05_059","05_060"], 
     ["05_061","05_062","05_063","05_064","05_065","05_066","05_067","05_068","05_069","05_070","05_071","05_072","05_073","05_074","05_075","05_076","05_077","05_078","05_079","05_080"], 
     ["05_081","05_082","05_083","05_084","05_085","05_086","05_087","05_088","05_089","05_090","05_091","05_092","05_093","05_094","05_095","05_096","05_097","05_098","05_099","05_100"], 
     ["05_101","05_102","05_103","05_104","05_105","05_106","05_107","05_108","05_109","05_110","05_111","05_112","05_113","05_114","05_115"] 
    ]; 

    a.addButton("emoticons_travel_places", { 
     type: "panelbutton", 
     panel: { 
      role: "application", 
      autohide: !0, 
      html: c, 
      onclick: function(b) { 
       var c = a.dom.getParent(b.target, "a"); 
       c && (a.insertContent('<img src="' + c.getAttribute("data-mce-url") + '" width="30" height="30" alt="' + c.getAttribute("data-mce-alt") + '" />'), this.hide()) 
      } 
     }, 
     tooltip: "Emoticons - Travel & Places" 
    }) 
});

凡var d = ...位被什么是AJAX调用返回所取代。

我不能重写整个代码，因为它被TinyMCE插件系统使用。

我觉得我很亲密，但一直在卡住，并且一直在关闭和关闭几天。

来源

2016-05-29 4532066

没有@idiot即可资讯从异步代码返回。你必须或者让请求同步（在UI线程中被删除）或者在成功回调中运行你的'a.addButton'代码。 –

我最终的答案，使用TimyMCE自己tinymce.util.XHR.send：

tinymce.util.XHR.send({ 
    url: 'emoji.php?cat=emoticons_travel_places', 
    success: function(returnedData) { 
     MyData = JSON.parse(returnedData); 
     d = MyData; 
     } 
});

在这里找到答案：

tinymce.util.XHR.send -> variable

更多通过TinyMCE的文档tinymce.util.XHR.send

来源

2016-05-31 18:26:03 4532066

从异步调用返回响应

回答

相关问题