http://jsfiddle.net/eYgGK/层次JSON与父ID
我偷了这个脚本从不同的职位:
function convertToHierarchy() {
var arry = [{ "Id": "1", "Name": "abc", "Parent": "", "attr": "abc" },
{ "Id": "2", "Name": "abc", "Parent": "1", "attr": "abc" },
{ "Id": "3", "Name": "abc", "Parent": "2", "attr": "abc" },
{ "Id": "4", "Name": "abc", "Parent": "2", "attr": "abc" }];
var nodeObjects = createStructure(arry);
for (var i = nodeObjects.length - 1; i >= 0; i--) {
var currentNode = nodeObjects[i];
if (currentNode.value.Parent === "") {
continue;
}
var parent = getParent(currentNode, nodeObjects);
if (parent === null) {
continue;
}
parent.children.push(currentNode);
nodeObjects.splice(i, 1);
}
console.dir(nodeObjects);
return nodeObjects;
}
function createStructure(nodes) {
var objects = [];
for (var i = 0; i < nodes.length; i++) {
objects.push({ value: nodes[i], children: [] });
}
return objects;
}
function getParent(child, nodes) {
var parent = null;
for (var i = 0; i < nodes.length; i++) {
if (nodes[i].value.Id === child.value.Parent) {
return nodes[i];
}
}
return parent;
}
此脚本生成:
[{
"value": {
"Id": "1",
"Name": "abc",
"Parent": "",
"attr": "abc"
},
"children": [{
"value": {
"Id": "2",
"Name": "abc",
"Parent": "1",
"attr": "abc"
},
"children": [{
"value": {
"Id": "4",
"Name": "abc",
"Parent": "2",
"attr": "abc"
},
"children": []
}, {
"value": {
"Id": "3",
"Name": "abc",
"Parent": "2",
"attr": "abc"
},
"children": []
}]
}]
}]
我正在寻找的是:
[{
"Id": "1",
"Name": "abc",
"Parent": "",
"attr": "abc",
"children": [{
"Id": "2",
"Name": "abc",
"Parent": "1",
"attr": "abc",
"children": [{
"Id": "4",
"Name": "abc",
"Parent": "2",
"attr": "abc"
}, {
"Id": "3",
"Name": "abc",
"Parent": "2",
"attr": "abc"
}]
}]
}]
我需要主要摆脱“价值”包装,其次是空的子节点。 我知道我可以写一个清理脚本,但那不会是最佳实践。 如果有人知道如何修复或建议一个不同的脚本,那将会很棒!
感谢
Great Work Arun !!太感谢了! – LastTribunal 2013-03-13 03:22:55
Arun,你知道我可以如何将“children”属性tittle重命名为“items”? – LastTribunal 2013-03-14 18:24:50
@ 655321查看更新 – 2013-03-15 00:00:59