PHP解码base64文件内容

Question

我有一个脚本获取文件的内容并使用base64对其进行编码。此脚本工作正常：

<?php 
$targetPath="D:/timekeeping/logs/94-20160908.dat"; 
$data = base64_encode(file_get_contents($targetPath)); 
$file = fopen($targetPath, 'w'); 
fwrite($file, $data); 
fclose($file); 
echo "file contents has been encoded"; 
?> 

现在，我想解码内容回到其原始值。我试过了：

<?php 
$targetPath="D:/timekeeping/logs/94-20160908.dat"; 
$data = base64_decode(file_get_contents($targetPath)); 
$file = fopen($targetPath, 'w'); 
fwrite($file, $data); 
fclose($file); 
echo "file contents has been decoded"; 
?> 

但是不行。

Answer 1

你没有提供的“不行”我想你双重编码或双解码becouse输入&输出相同的文件都是细节，考虑

<?php 

$in = 'teszt'; 
$enc = base64_encode($in); 
echo $enc,"\n"; 
$enc2 = base64_encode($enc); 
echo $enc2,"\n"; 
$enc3 = base64_encode($enc2); 
echo $enc3,"\n"; 

看到双编码

会发生什么

试试这个

<?php 
$sourcePath="D:/timekeeping/logs/94-20160908.dec.dat"; 
$targetPath="D:/timekeeping/logs/94-20160908.enc.dat"; 
if (!file_exsits($sourcePath) || !file_readable($sourcePath)) { 
    die('missing source'); 
} 
$source = file_get_contents($sourcePath); 
if (empty($source)) { 
    die('source file is empty'); 
} 
$data = base64_encode($source); 
$file = fopen($targetPath, 'w'); 
fwrite($file, $data); 
fclose($file); 
echo "file contents has been encoded"; 
?> 

<?php 
$sourcePath="D:/timekeeping/logs/94-20160908.enc.dat"; 
$targetPath="D:/timekeeping/logs/94-20160908.dec.dat"; 
if (!file_exsits($sourcePath) || !file_readable($sourcePath)) { 
    die('missing source'); 
} 
$source = file_get_contents($sourcePath); 
if (empty($source)) { 
    die('source file is empty'); 
} 
$data = base64_decode($source); 
$file = fopen($targetPath, 'w'); 
fwrite($file, $data); 
fclose($file); 
echo "file contents has been decoded"; 
?> 

Answer 2

这个固定我的问题。这两个函数不能很好地结合在一起，所以我分开file_get_contents base64_decode

<?php 
    $targetPath="D:/timekeeping/logs/94-20160908.dat"; 
    $data = file_get_contents($targetPath); 
    $content= base64_decode($data); 
    $file = fopen($targetPath, 'w');  
    fwrite($file, $content); 
    fclose($file); 
    echo "done"; 
?>