2017-07-26 98 views
1

我有一个对象数组addon_categories包含一个属性id和另一个数组:addons。当用户切换复选框时,状态应该相应更新:其中包括添加或删除所选类别下的“addons”数组。如何通过更新对象数组中特定对象内的数组来更新状态?

this.state = { addon_categories: [] }; 

// example of filled state 
this.state = { addon_categories: [ 
    { id: 3, addons: [ 1 ] }, 
    { id: 2, addons: [ 1, 4, 11 ] }, 
    { id: 4, addons: [ 3, 4] } 
] }; 

这是更的JavaScript多于React的问题的不同之处在于数据必须被最终更新为成分的状态。作为JavaScript的初学者,我无法用包含一些属性和数组的对象数组来更新状态对象。在下面的代码中,为特定类别更新addons数组(适用于删除和推送)的正确逻辑是什么?

这里的逻辑:

  1. 如果类别ID不存在,简单地增加一个新的对象与该类别ID和附加元件阵列与单个附加ID。 [✓]

  2. 如果类别ID存在,
    - >检查addon_id是否存在于此类别中。
    - >如果addon_id存在于此类别中,请从此对象中的addons数组中删除addon id [?]
    - >如果addon_id不存在,请将此addon id插入此对象中的addons数组[

这是我的代码。

import React from 'react'; 
import { connect } from 'react-redux'; 
import store from '../../../../reducers/store'; 
import fetchFood from '../../../../actions/restaurant/food_get'; 

class AddonsModal extends React.Component 
{ 
    constructor(props) 
    { 
     super(props); 
     this.state = { addon_categories: [] }; 

     this.onAddonChange = this.onAddonChange.bind(this); 
    } 

    /* 
    * Handle click, toggle addon change 
    */ 
    onAddonChange(e) 
    { 
     const c = +e.target.name; // category_id from input 
     const a = +e.target.id; // addon_id from input 

     // create new instance of this.state.addon_categories 
     let addon_categories = this.state.addon_categories.slice(); 

     if (!this.addonCategoryExists(c)) 
     { 
      // CATEGORY DOESNT EXIST, SO NEW CATEGORY AND ADDON ADDED! 
      addon_categories.push({ id: c, addons: [a] }); 
      this.setState({ addon_categories },() => console.log('NEW STATE', this.state.addon_categories)); 
     } 
     else 
     { 
      // CATEGORY EXISTS 
      if (this.addonExistsInCategory(c, a)) 
      { 
       // ?? ADDON EXISTS IN THIS CATEGORY, SO NEED TO REMOVE IT 
      } 
      else 
      { 
       // ?? ADDON DOESNT EXIST IN CATEGORY SO NEED TO ADD IT TO JUST THIS CATEGORY 
      } 
     } 

    } 

    addonCategoryExists(c) 
    { 
     return !! this.state.addon_categories.filter(category => category.id === c).length; 
    } 

    addonExistsInCategory(c, a) 
    { 
     let verified = false; 
     let categories = this.state.addon_categories.filter(category => category.id === c); 
     categories.forEach(category => 
     { 
      if (category.addons.includes(a)) { verified = true; } 
     }); 
     return verified; 
    } 

    componentDidMount() 
    { 
     store.dispatch(fetchFood(this.props.Restaurant.id, this.props.food.id)); 
    } 

    render() 
    { 
     let food = this.props.food; 
     let foodData = this.props.foodDetails.food.data; 
     let addon_categories = foodData ? foodData.data.addon_category : null; 

     return (


          <div className="row"> 

           {addon_categories && addon_categories.map(category => { return (

            <div className="col-xs-12" key={category.id}> 
             <div className="pop-up-dish-specials"> 
              <h2>{category.name}</h2> 

              {category.addons && category.addons.map(addon => { return (

               <div key={addon.id}> 
                {/* for simplicity, i've sent the category_id in name and addon_id in id property */} 
                <input type="checkbox" name={category.id} id={addon.id} onChange={this.onAddonChange}/> 
                <label htmlFor={addon.id}>{addon.name}</label> 
               </div> 

              )})} 

             </div> 
            </div> 

           )})} 

          </div> 


     ) 
    } 
} 

function mapStateToProps(state) 
{ 
    return { foodDetails: state.foodDetails } 
} 

export default connect(mapStateToProps)(AddonsModal); 

回答

1

我只想用简单的.MAP和.filter如果插件存在,因此去除:

const newCategories = this.state.addon_categories.map(category => { 
    if (category.id === c) { 
     const newAddons = category.addons.filter(addon => addon !== a); 
     return { id: category.id, addons: newAddons }; 
    } else { 
     return category; 
    }   
}); 
this.setState({ addon_categories: newCategories }); 

添加它会是这样:

const newCategories = this.state.addon_categories.map(category => { 
    if (category.id === c) { 
     const newAddons = category.addons.concat([a]) 
     return { id: category.id, addons: newAddons }; 
    } else { 
     return category; 
    }   
}); 
this.setState({ addon_categories: newCategories }); 

尽管这个问题可能有更好的解决方案。

+0

这是很好的解决方案,非常感谢。 – anonym

+0

我想进一步分解两个删除条件。 '[#1]'删除整个'addon_category对象',如果它是其中唯一的插件,'[#2。]'如果有多个(完成✓),就从阵列中删除插件。我无法使用'if(category.id === c && category.addons.length === 1){return addon_categories.splice(index,1); }' – anonym

+0

您的解决方案将无法正常工作,因为拼接会返回已删除的项目,因此它不会对您有所帮助。你可以做2件事 - 或者只是修改我的代码返回到这样的'newAddons.length? {id:category.id,addons:newAddons}:undefined',然后在设置状态时,您将执行addon_categories:newCategories.filter(category => category)'(这样您可以从数组中过滤一个未定义的值。这样做是为了保存类别索引值,然后在设置状态之前使用splice从newCategories中删除它。 –

1
if (this.addonExistsInCategory(c, a)) { 
     // ADDON EXISTS IN THIS CATEGORY, SO NEED TO REMOVE IT 
     addon_categories.find(function(obj) { 
     if (obj.id == c) { 
      obj.addons.splice(obj.addons.indexOf(a), 1); 
     } 
     }); 
    } else { 
     // ADDON DOESNT EXIST IN CATEGORY SO NEED TO ADD IT TO JUST THIS CATEGORY 
     addon_categories.find(function(obj) { 
     if (obj.id == c) { 
      obj.addons.push(a); 
     } 
     }); 
    } 
this.setState({ addon_categories },() => console.log('NEW STATE', this.state.addon_categories)); 
+0

@Oliver如果这样可以解决您的查询问题,那么您可以将其标记为答案 –

+0

这样可以解决您的问题,而非您的问题。 – anonym