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我已将下列程序作为我学术项目的一部分。由于我无法确定实际问题，因此我已经给出了整个程序。下面多线程程序中的分段错误C
#include<stdio.h>
#include<math.h>
#include<pthread.h>
//Structure for getting dam details
struct dam
{
float max_height;
float min_height;
float sto_capacity;
float pro_capacity;
float stn_const;
float crnt_lvl;
float delay;
float crnt_lvl_min;
float crnt_lvl_max;
float unit_vol;
float water_req;
float work_hr;
int work_hr_int;
};
//global variables
int n, i, extra_w_hr_int, extra_w_hr_ref, j, k, flag, l, m, swap, pos=11, h, main_flag=1, days_count=0, temp_extra_w_hr_ref;
int jj, k1, flag1, l1, m1, swap1, g=0;
float extra_w_hr, extra_height, diff_level, extra_water;
int rank[24];
int rank1[24];
float rate[24];
float water_pu[24];
float sum_rate1[24];
float avg_rate1[24];
float std_dev_rate1[24];
float temp_rate1[24];
float sum_rate[24];
float avg_rate[24];
float std_dev_rate[24];
float temp_rate[24];
struct dam dam_obj[10];
pthread_t inner_thread[10];
//Thread for increasing water in lower dam after delay
void *inner_function(void *no)
{
int *num = no;
if(*num != (n-1))
{
sleep(dam_obj[*num-1].delay);
}
else if(*num == (n-1))
{
sleep(dam_obj[*num].delay);
}
dam_obj[*num+1].unit_vol = dam_obj[*num+1].sto_capacity/(dam_obj[*num+1].max_height - dam_obj[*num+1].min_height);
extra_height = extra_water/dam_obj[*num+1].unit_vol;
dam_obj[*num+1].crnt_lvl+=extra_height;
pthread_exit(NULL);
}
//Thread for forcasting 7 day details
void *days_function()
{
while(days_count<7)
{
h=n-2;
while(h>=(pos-1))
{
printf("Day-%d\tWorking Hours of dam %d:\t18hrs to 22hrs\n", days_count+1, h);
dam_obj[h].water_req = (dam_obj[h].pro_capacity*dam_obj[h].work_hr)/(1000*dam_obj[h].stn_const);
if((h-1)>-1)
{
dam_obj[h-1].work_hr = dam_obj[h].water_req*1000*dam_obj[h].stn_const/dam_obj[h-1].pro_capacity;
dam_obj[h-1].work_hr_int = dam_obj[h-1].work_hr*10;
temp_extra_w_hr_ref = dam_obj[h-1].work_hr_int%10;
dam_obj[h-1].work_hr_int/=10;
if(temp_extra_w_hr_ref>2)
{
dam_obj[h-1].work_hr_int++;
}
dam_obj[h-1].work_hr_int-=4;
//calculate the average and standard deviation of the rates
jj=0;
k1=1;
flag1=1;
while(flag1=1)
{
if(jj==0 && k1==0)
{
flag1=0;
break;
}
if(jj>=18 && jj<=22 && (jj+dam_obj[h-1].work_hr_int)>=18 && (jj+dam_obj[h-1].work_hr_int)<=22)
{
rank1[jj]=25;
jj++;
sum_rate1[jj]=0;
avg_rate1[jj]=0;
std_dev_rate1[jj]=0;
continue;
}
rank1[jj]=jj;
k1=0;
sum_rate1[jj] = 0;
for(l1=0;l1<dam_obj[h-1].work_hr_int;l1++)
{
m1 = jj+l1;
if(m1>23)
{
m1-=24;
}
sum_rate1[jj]+=rate[m1];
}
avg_rate1[jj]=sum_rate1[jj]/extra_w_hr_int;
for(l1=0;l1<dam_obj[h-1].work_hr_int;l1++)
{
m1 = jj+l1;
if(m1>23)
{
m1-=24;
}
temp_rate1[m1]=rate[m1];
temp_rate1[m1]=pow((temp_rate1[m1]-avg_rate1[m1]),2);
std_dev_rate1[jj]+=temp_rate1[m1];
}
jj++;
if(jj>23)
{
jj-=24;
}
}
//Sorting the values
for(jj=0;jj<(n-1);jj++)
{
for(l1=0;l1<n-jj-1;l1++)
{
if((avg_rate1[l1]>avg_rate1[l1+1]) || ((avg_rate1[l1]==avg_rate1[l1+1]) && (std_dev_rate1[l1]>std_dev_rate1[l1+1])))
{
swap1=rank1[l1];
rank1[l1]=rank[l1+1];
rank[l1+1]=swap1;
}
}
}
printf("Day-%d\tWorking Hours of dam %d:\t18hrs to 22hrs\tand\t%dhrs to %dhrs\n", days_count+1, h-1, rank1[0], rank1[0]+dam_obj[h-1].work_hr_int);
}
h--;
}
while(g<(pos-1))
{
printf("Day-%d\tWorking Hours of dam 1:\t18hrs to 22hrs\n", days_count+1);
dam_obj[g].water_req = dam_obj[g].pro_capacity*dam_obj[g].work_hr/(1000*dam_obj[g].stn_const);
dam_obj[g+1].work_hr = dam_obj[g].water_req*1000*dam_obj[g+1].stn_const/dam_obj[g+1].pro_capacity;
dam_obj[g+1].work_hr_int = dam_obj[g+1].work_hr*10;
temp_extra_w_hr_ref = dam_obj[g+1].work_hr_int%10;
dam_obj[g+1].work_hr_int/=10;
if(temp_extra_w_hr_ref>2)
{
dam_obj[g+1].work_hr_int++;
}
dam_obj[g+1].work_hr_int-=4;
//calculate the average and standard deviation of the rates
jj=0;
k1=1;
flag1=1;
while(flag1=1)
{
if(jj==0 && k1==0)
{
flag1=0;
break;
}
if(jj>=18 && jj<=22 && (jj+dam_obj[g+1].work_hr_int)>=18 && (jj+dam_obj[g+1].work_hr_int)<=22)
{
rank1[jj]=25;
jj++;
sum_rate1[jj]=0;
avg_rate1[jj]=0;
std_dev_rate1[jj]=0;
continue;
}
rank1[jj]=jj;
k1=0;
sum_rate1[jj] = 0;
for(l1=0;l1<dam_obj[g+1].work_hr_int;l1++)
{
m1 = jj+l1;
if(m1>23)
{
m1-=24;
}
sum_rate1[jj]+=rate[m1];
}
avg_rate1[jj]=sum_rate1[jj]/extra_w_hr_int;
for(l1=0;l1<dam_obj[g+1].work_hr_int;l1++)
{
m1 = jj+l1;
if(m1>23)
{
m1-=24;
}
temp_rate1[m1]=rate[m1];
temp_rate1[m1]=pow((temp_rate1[m1]-avg_rate1[m1]),2);
std_dev_rate1[jj]+=temp_rate1[m1];
}
jj++;
if(jj>23)
{
jj-=24;
}
}
//Sorting the values
for(jj=0;jj<(n-1);jj++)
{
for(l1=0;l1<n-jj-1;l1++)
{
if((avg_rate1[l1]>avg_rate1[l1+1]) || ((avg_rate1[l1]==avg_rate1[l1+1]) && (std_dev_rate1[l1]>std_dev_rate1[l1+1])))
{
swap1=rank1[l1];
rank1[l1]=rank[l1+1];
rank[l1+1]=swap1;
}
}
}
printf("Day-%d\tWorking Hours of dam %d:\t18hrs to 22hrs\tand\t%dhrs to %dhrs\n", days_count+1, g+2, rank1[0], rank1[0]+dam_obj[g+1].work_hr_int);
g++;
}
dam_obj[n-1].water_req = dam_obj[g].water_req - dam_obj[g-1].water_req;
dam_obj[n-1].work_hr = dam_obj[n-1].water_req*1000*dam_obj[n-1].stn_const/dam_obj[n-1].pro_capacity;
dam_obj[n-1].work_hr_int = dam_obj[n-1].work_hr*10;
temp_extra_w_hr_ref = dam_obj[n-1].work_hr_int%10;
dam_obj[n-1].work_hr_int/=10;
if(temp_extra_w_hr_ref>2)
{
dam_obj[n-1].work_hr_int++;
}
dam_obj[n-1].work_hr_int-=4;
//calculate the average and standard deviation of the rates
jj=0;
k1=1;
flag1=1;
while(flag1=1)
{
if(jj==0 && k1==0)
{
flag1=0;
break;
}
if(jj>=18 && jj<=22 && (jj+dam_obj[n-1].work_hr_int)>=18 && (jj+dam_obj[n-1].work_hr_int)<=22)
{
rank1[jj]=25;
jj++;
sum_rate1[jj]=0;
avg_rate1[jj]=0;
std_dev_rate1[jj]=0;
continue;
}
rank1[jj]=jj;
k1=0;
sum_rate1[jj] = 0;
for(l1=0;l1<dam_obj[n-1].work_hr_int;l1++)
{
m1 = jj+l1;
if(m1>23)
{
m1-=24;
}
sum_rate1[jj]+=rate[m1];
}
avg_rate1[jj]=sum_rate1[jj]/extra_w_hr_int;
for(l1=0;l1<dam_obj[h-1].work_hr_int;l1++)
{
m1 = jj+l1;
if(m1>23)
{
m1-=24;
}
temp_rate1[m1]=rate[m1];
temp_rate1[m1]=pow((temp_rate1[m1]-avg_rate1[m1]),2);
std_dev_rate1[jj]+=temp_rate1[m1];
}
jj++;
if(jj>23)
{
jj-=24;
}
}
//Sorting the values
for(jj=0;jj<(n-1);jj++)
{
for(l1=0;l1<n-jj-1;l1++)
{
if((avg_rate1[l1]>avg_rate1[l1+1]) || ((avg_rate1[l1]==avg_rate1[l1+1]) && (std_dev_rate1[l1]>std_dev_rate1[l1+1])))
{
swap1=rank1[l1];
rank1[l1]=rank[l1+1];
rank[l1+1]=swap1;
}
}
}
printf("Day-%d\tWorking Hours of dam %d:\t18hrs to 22hrs\tand\t%dhrs to %dhrs\n", days_count+1, n-1, rank1[0], rank1[0]+dam_obj[n-1].work_hr_int);
}
pthread_exit(NULL);
}
//Thread function for working of dams
void *dam_function()
{
diff_level = dam_obj[i].crnt_lvl - dam_obj[i].crnt_lvl_max;
dam_obj[i].unit_vol = dam_obj[i].sto_capacity/(dam_obj[i].max_height - dam_obj[i].min_height);
extra_water = diff_level * dam_obj[i].unit_vol;
water_pu[i] = dam_obj[i].pro_capacity/(dam_obj[i].stn_const * 1000);
extra_w_hr = extra_water/water_pu[i];
extra_w_hr_int = extra_w_hr*10;
extra_w_hr_ref = extra_w_hr_int%10;
extra_w_hr_int/=10;
if(extra_w_hr_ref>2)
{
extra_w_hr_int++;
}
//calculate the average and standard deviation of the rates
j=0;
k=1;
flag=1;
while(flag=1)
{
if(j==0 && k==0)
{
flag=0;
break;
}
if(j>=18 && j<=22 && (j+extra_w_hr_int)>=18 && (j+extra_w_hr_int)<=22)
{
rank[j]=25;
j++;
sum_rate[j]=0;
avg_rate[j]=0;
std_dev_rate[j]=0;
continue;
}
rank[j]=j;
k=0;
sum_rate[j] = 0;
for(l=0;l<extra_w_hr_int;l++)
{
m = j+l;
if(m>23)
{
m-=24;
}
sum_rate[j]+=rate[m];
}
avg_rate[j]=sum_rate[j]/extra_w_hr_int;
std_dev_rate[j]=0;
for(l=0;l<extra_w_hr_int;l++)
{
m = j+l;
if(m>23)
{
m-=24;
}
temp_rate[m]=rate[m];
temp_rate[m]=pow((temp_rate[m]-avg_rate[m]),2);
std_dev_rate[j]+=temp_rate[m];
}
j++;
if(j>23)
{
j-=24;
}
}
//Sorting the values
for(j=0;j<(n-1);j++)
{
for(l=0;l<n-j-1;l++)
{
if((avg_rate[l]>avg_rate[l+1]) || ((avg_rate[l]==avg_rate[l+1]) && (std_dev_rate[l]>std_dev_rate[l+1])))
{
swap=rank[l];
rank[l]=rank[l+1];
rank[l+1]=swap;
}
}
}
printf("Hours of extra running: %d\nExtra Working Hours for dam-%d: %d Hours - %d Hours\n", extra_w_hr_int, i, rank[0], rank[0]+extra_w_hr_int);
if(i+1<n)
{
pthread_create (&inner_thread[i], NULL, (void *) &inner_function, &i);
if(i == pos)
{
pthread_create (&inner_thread[pos], NULL, (void *) &inner_function, &pos);
}
}
pthread_exit(NULL);
}
int main()
{
pthread_t thread[10],days_thread;
FILE *file = fopen ("values.txt", "r");
dam_obj[n-1].work_hr = 4;
dam_obj[0].work_hr = 24;
//printf("Enter the number of dams:\t\t");
fscanf(file, "%d\n",&n);
//printf("\n\nThe branched dam should be given as the \'n\'th dam in the set\n\n\n");
for(i=0;i<n;i++)
{
//printf("Enter the maximum height of dam-%d:\t",i+1);
fscanf(file, "%f\n",&dam_obj[i].max_height);
//printf("Enter the minimum height of dam-%d:\t",i+1);
fscanf(file, "%f\n",&dam_obj[i].min_height);
//printf("Enter the storage capacity of dam-%d:\t",i+1);
fscanf(file, "%f\n",&dam_obj[i].sto_capacity);
//printf("Enter the production capacity of dam-%d:\t",i+1);
fscanf(file, "%f\n",&dam_obj[i].pro_capacity);
//printf("Enter the station constant of dam-%d:\t",i+1);
fscanf(file, "%f\n",&dam_obj[i].stn_const);
//printf("Enter the current level of dam-%d:\t",i+1);
fscanf(file, "%f\n",&dam_obj[i].crnt_lvl);
//printf("Enter the time delay of dam-%d:\t\t",i+1);
fscanf(file, "%f\n",&dam_obj[i].delay);
}
//printf("Enter the rates for the following hours:\n");
for(i=0;i<24;i++)
{
//printf("%d-%d:\t\t\t",i,i+1);
fscanf(file, "%f\n",&rate[i]);
}
if(n>2)
{
//printf("Enter the position at which the stage occurs:\t");
fscanf(file, "%d\n",&pos);
}
for(i=0;(i<n && days_count<7);i++)
{
dam_obj[i].crnt_lvl_min=dam_obj[i].max_height * 0.6;
dam_obj[i].crnt_lvl_max=dam_obj[i].max_height * 0.8;
//If the current level is greater than allowed maximum level
if(dam_obj[i].crnt_lvl_max < dam_obj[i].crnt_lvl)
{
pthread_create (&thread[i], NULL, (void *) &dam_function, NULL);
if(i==(n-1))
{
i = -1;
days_count++;
}
}
//Normal Working Condition
else if(((dam_obj[i].crnt_lvl<dam_obj[i].crnt_lvl_max) && (dam_obj[i].crnt_lvl>dam_obj[i].crnt_lvl_min)) && (main_flag == 1))
{
main_flag=0;
pthread_create (&days_thread, NULL, (void *) &days_function, NULL);
}
}
pthread_exit(NULL);
}
文件的内容给出：
5
1758.69
1735.836
7.787
28
1.263
1758.69
2
847.6
844.86
1.614
36
.79
847.05
4
456.59
444
5.557
55
.41
452.9
3
253
237.74
4.55
116
.46
247.3
0
707.745
678.8
47.4
32
.472
703.8
2
7
5
6
3
8
3
6
4
5
7
9
1
3
2
4
5
7
8
4
6
7
3
5
9
3
我编译使用gcc -o project project.c -pthread -lpthread -lm 在Linux中程序但在运行它返回只是一个Segmentation Fault。所以，我编译的代码使用gdb调试，之后上运行，GDB结果如下：
Starting program: /home/anver/project
[Thread debugging using libthread_db enabled]
[New Thread 0xb7e2db70 (LWP 3778)]
[New Thread 0xb762cb70 (LWP 3779)]
[New Thread 0xb6e2bb70 (LWP 3780)]
[New Thread 0xb662ab70 (LWP 3781)]
Program received signal SIGSEGV, Segmentation fault.
[Switching to Thread 0xb762cb70 (LWP 3779)]
0x08049cd1 in dam_function() at project-file.c:504
504 std_dev_rate[j]+=temp_rate[m];
后，当我打印的J，L值和M我想通了，我得到非常高的值对于j，l和m来说，这是预计不会超过23的。无论如何我可以解决这个问题吗？提前致谢。
没有人会花费他们的下午看600多行代码。您有责任提供最小的，可口的测试用例。 – 2013-04-10 18:35:08
你给出了发布这个代码墙的基本原理，你不知道问题出在哪里，但没有gdb为你做这件事？ （'std_dev_rate [j] + = temp_rate [m];'） – antonijn 2013-04-10 18:35:53
我给出了整个代码，因为我找不出实际问题在哪里。正如你所看到的，程序中使用了很多变量和线程，我无法弄清楚任何线索。我已经包含了gdb的结果，所以很容易检查出来。 – 2013-04-10 18:37:32