使用哪里都不在CI

Question

$result3=$this->hrdb->select(array('concat(eb.first_name," ",eb.middle_name, " ",eb.last_name,"") as emp_name','eb.id','pp.emp_id','pp.gross_monthly','pp.amount as net_amount','pp.payslip_id','eor.dep_id')) 
        ->where('pp.emp_id' not_in     (select(array('pp.gross_monthly','pp.emp_id','pp.amount as net_amount','pp.payslip_id'))),Null,FALSE) 
        ->from('payroll_payments as pp') 
        ->join('employee_basic as eb','pp.emp_id=eb.id','left') 
        ->join('employee_org as eor','pp.emp_id=eor.emp_id','left') 
        ->order_by($_field, $params['_sort_direction']) 
        ->where(array('pp.npyear'=>$params['nep_year'],'pp.npmonth'=>$params['nep_month2'])) 
        ->get() 
        ->result(); 

查询是我写的查询，但问题出现了，告诉

Parse error: syntax error, unexpected T_STRING in /var/www/html/vianet_db/htdocs/addons/shared_addons/modules/hrm/models/payslip_m.php on line 558

Answer 1

使用concat(eb.first_name." ".eb.middle_name." ".eb.last_name."") as emp_name和检查。从查询中删除'引用并简单地添加字段名称。而不是'eb.id','pp.emp_id'，请使用eb.id,pp.emp_id。在选择部分的所有字段和数组ID不需要的情况下执行此操作。

Answer 2

您需要在SELECT中添加第二个可选参数FALSE（首先也选择），以免自动转义字符。

$subqueryResult = //your subquery result in array 

$result3=$this->hrdb->select(array('concat(eb.first_name," ",eb.middle_name, " ",eb.last_name,"") as emp_name','eb.id','pp.emp_id','pp.gross_monthly','pp.amount as net_amount','pp.payslip_id','eor.dep_id'), FALSE) 
        ->from('payroll_payments as pp') 
        ->join('employee_basic as eb','pp.emp_id=eb.id','left') 
        ->join('employee_org as eor','pp.emp_id=eor.emp_id','left') 
        ->where_not_in('pp.emp_id', $subqueryResult) 
        ->where(array('pp.npyear'=>$params['nep_year'],'pp.npmonth'=>$params['nep_month2'])) 
        ->order_by($_field, $params['_sort_direction']) 
        ->get() 
        ->result();